65x+87x+42x=
\( \frac{5}{6}x+\frac{7}{8}x+\frac{2}{4}x= \)
\( x(\frac{1}{3}+\frac{1}{2})= \)
\( (\frac{1}{3}+\frac{9}{11})\times33= \)
\( (\frac{1}{3}+\frac{5}{12})\times24= \)
\( 9(\frac{1}{3}+\frac{1}{4})= \)
First, let's find a common denominator for 4, 8, and 6: it's 24.
Now, we'll multiply each fraction by the appropriate number to get:
Let's solve the multiplication exercises in the numerator and denominator:
We'll connect all the numerators:
Let's break down the numerator into a smaller addition exercise:
\( -3+(-\frac{1}{2})+(\frac{3}{8})+\frac{5}{8}= \)
\( -\frac{1}{2}+\frac{3}{4}+-\frac{1}{5}+(-\frac{4}{5})= \)
\( -\frac{4}{9}+5+(-2)+\frac{5}{9}= \)
\( -5+-\frac{1}{2}+10+(-\frac{3}{4})= \)
\( -\frac{3}{8}-(-\frac{5}{8})-(-\frac{1}{2})= \)
\( -\frac{14}{7}+(-3)-\frac{1}{2}-(-\frac{1}{4})= \)
Solve:
\( -\frac{4}{16}-(-\frac{3}{8})+\frac{2}{8}+(-\frac{1}{4})= \)
\( (\frac{1}{4}+\frac{7}{4}-\frac{5}{4}-\frac{1}{4})\cdot10:7:5=\text{?} \)
Solve: