Addition of Fractions: In combination with other operations

$(\frac{1}{4}+\frac{7}{4}-\frac{5}{4}-\frac{1}{4})\cdot10:7:5=\text{?}$

$\frac{1}{7}$

Choose the exercise for the highest result

$\frac{1}{2}+\frac{3}{10}$

Solve the following exercise:

$\frac{2}{5}+\frac{1}{2}-\frac{1}{3}=\text{?}$

$\frac{17}{30}$

Solve the following exercise:

$\frac{6}{7}-\frac{1}{2}+\frac{3}{14}=\text{?}$

$\frac{8}{14}$

Solve the following exercise:

$\frac{9}{10}-\frac{4}{5}+\frac{1}{2}=\text{?}$

$\frac{6}{10}$

Solve the following exercise:

$\frac{2}{7}+\frac{1}{2}-\frac{7}{14}=\text{?}$

$\frac{4}{14}$

Solve the following exercise:

$\frac{4}{10}+\frac{1}{5}-\frac{1}{2}=\text{?}$

$\frac{1}{10}$

Solve the following exercise:

$\frac{3}{8}+\frac{1}{2}-\frac{1}{4}=\text{?}$

$\frac{5}{8}$

$\frac{1}{4}-\frac{3}{4}+\frac{1}{2}+\frac{5}{10}=$

$\frac{1}{2}$

$\frac{3}{5}+\frac{1}{5}-\frac{3}{15}=$

$\frac{3}{5}$

$\frac{3}{5}-\frac{1}{5}+\frac{3}{15}=$

$\frac{3}{5}$

$\frac{3}{6}-\frac{2}{4}+\frac{1}{12}=$

$\frac{1}{12}$

$\frac{3}{6}+\frac{2}{4}-\frac{1}{12}=$

$\frac{11}{12}$

$\frac{2}{3}+\frac{2}{15}-\frac{4}{5}=$

$0$

$\frac{1}{3}+\frac{7}{15}-\frac{2}{5}=$

$\frac{2}{5}$

$\frac{1}{4}+\frac{3}{4}+\frac{3}{20}-\frac{5}{10}=$

$\frac{13}{20}$

$\frac{1}{4}-\frac{3}{4}+\frac{1}{2}-\frac{5}{10}=$

$-\frac{1}{2}$