Solve the following equation:
Solve the following equation:
\( \frac{3}{5}-\frac{3}{10}= \)
Solve the following equation:
\( \frac{4}{5}-\frac{5}{10}= \)
Solve the following equation:
\( \frac{4}{5}-\frac{3}{10}= \)
Solve the following exercise:
\( \frac{2}{3}-\frac{1}{9}=\text{?} \)
Solve the following exercise:
\( \frac{5}{4}-\frac{3}{8}=\text{?} \)
Solve the following equation:
Let's begin by identifying the lowest common denominator between 5 and 10.
In order to determine the lowest common denominator, we need to find a number that is divisible by both 5 and 10.
In this case, the common denominator is 10.
Let's proceed to multiply each fraction by the appropriate number to reach the denominator 10.
We'll multiply the first fraction by 2
We'll multiply the second fraction by 1
Finally let's subtract as follows:
Solve the following equation:
Let's begin by determining the lowest common denominator between 5 and 10.
In order to identify the lowest common denominator, we must find a number that is divisible by both 5 and 10.
In this case, the common denominator is 10
Let's proceed to multiply each fraction by the appropriate number in order to reach the denominator 10.
We'll multiply the first fraction by 2
We'll multiply the second fraction by 1
Finally let's subtract as follows:
Solve the following equation:
Let's begin by identifying the lowest common denominator between 5 and 10.
In order to determine the lowest common denominator, we must find a number that is divisible by both 5 and 10.
In this case, the common denominator is 10.
Now let's proceed to multiply each fraction by the appropriate number to reach the denominator 10.
We'll multiply the first fraction by 2
We'll multiply the second fraction by 1
Finally let's subtract as follows:
Solve the following exercise:
To solve the problem of subtracting from , we need a common denominator. Let's follow these steps:
Thus, the difference between and is .
Therefore, the correct choice from the given options is .
Solve the following exercise:
To solve this problem, we'll perform the following steps:
Let's apply these steps starting with the first one.
Step 1: Find the Least Common Denominator
The denominators are and . The least common denominator is the smallest number that both denominators divide into evenly. In this case, the LCD is because it is the smallest number that is a multiple of both and .
Step 2: Convert fractions to have the same denominator of
- The fraction needs to be converted to a denominator of . To do this, multiply both the numerator and denominator by :
- The fraction already has the denominator , so it remains unchanged as .
Step 3: Subtract the numerators
Now that the fractions have the same denominator, subtract the numerators:
Therefore, the solution to is .
Solve the following exercise:
\( \frac{3}{4}-\frac{3}{8}=\text{?} \)
Solve the following exercise:
\( \frac{1}{2}-\frac{2}{8}=\text{?} \)
Solve the following exercise:
\( \frac{1}{2}-\frac{1}{4}=\text{?} \)
Solve the following exercise:
\( \frac{1}{4}-\frac{1}{8}=\text{?} \)
Solve the following exercise:
\( \frac{1}{2}-\frac{2}{10}=\text{?} \)
Solve the following exercise:
To solve the problem, we'll follow these steps:
Now, let's work through each step:
Step 1: Find a common denominator for the fractions and . The least common denominator is 8.
Convert to an equivalent fraction with a denominator of 8:
Step 2: Subtract from :
Step 3: There is no need to simplify further as the fraction is already in its simplest form.
Therefore, the solution to the problem is .
Solve the following exercise:
To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: The problem gives us the fractions and . The denominator can be converted to (the denominator of the second fraction) by multiplying by 4.
Step 2: Convert to , since . Now both fractions have a denominator of 8.
Step 3: Perform the subtraction: .
Step 4: Simplify by dividing both numerator and denominator by 2: .
Therefore, the solution to the problem is .
Solve the following exercise:
To solve the subtraction , follow these steps:
Therefore, the solution to is .
Solve the following exercise:
To solve the problem , we need to subtract these two fractions:
Step 1: Determine the common denominator.
The denominators are 4 and 8. The least common multiple of 4 and 8 is 8.
Step 2: Convert each fraction to an equivalent fraction with the common denominator of 8.
- Convert to
- The fraction already has the denominator 8.
Step 3: Subtract the numerators.
Subtract from :
The resulting fraction is already in its simplest form.
Therefore, the solution to the problem is .
Solve the following exercise:
To solve this fraction subtraction problem, we'll follow these steps:
Let's go through each step:
Step 1: Convert into a fraction with a denominator of .
We know that is equivalent to multiplying the numerator and the denominator by :
Step 2: Subtract from .
Subtract by keeping the denominator and subtract the numerators:
Step 3: Simplify the result.
The fraction is already in its simplest form.
Therefore, the solution to the problem is .
Solve the following exercise:
\( \frac{3}{5}-\frac{6}{15}=\text{?} \)
Solve the following exercise:
\( \frac{5}{6}-\frac{7}{12}=\text{?} \)
Solve the following exercise:
\( \frac{3}{4}-\frac{5}{12}=\text{?} \)
Solve the following exercise:
\( \frac{2}{3}-\frac{1}{6}=\text{?} \)
Solve the following exercise:
\( \frac{3}{5}-\frac{5}{10}=\text{?} \)
Solve the following exercise:
To solve , we need both fractions to have the same denominator. We observe that 15 is a multiple of 5, so it is already suitable as a common denominator.
Step 1: Convert
Convert to have a denominator of 15. Multiply both the numerator and the denominator by 3:
Step 2: Subtract the fractions
Now, subtract :
Step 3: Simplify the result
Simplify by dividing both the numerator and the denominator by 3:
Therefore, the solution to the problem is .
Solve the following exercise:
To solve the subtraction , we need a common denominator.
Step 1: Find the least common denominator (LCD) of the two fractions.
The denominators are 6 and 12. The least common multiple of 6 and 12 is 12.
Step 2: Convert to an equivalent fraction with a denominator of 12.
We can multiply the numerator and the denominator by 2 to achieve this:
.
Step 3: Now, subtract the fractions with a common denominator:
.
Step 4: Simplify the result.
can be simplified by dividing both the numerator and the denominator by 3:
.
Therefore, the solution to the problem is .
From the available choices, option 4, which is , is the correct answer.
Solve the following exercise:
To solve the problem , we need to subtract two fractions with different denominators. Let's follow these steps:
Therefore, the solution to the problem is .
Solve the following exercise:
To solve the problem , we follow these steps:
Therefore, the solution to the problem is .
Solve the following exercise:
To solve this problem, we'll follow a step-by-step approach:
Step 1: Convert both fractions to have the same denominator.
- The original fractions are and .
- Convert to a fraction with denominator 10. Multiply both numerator and denominator by 2:
.
Step 2: Subtract the fractions now that they have a common denominator.
- The fractions to subtract are .
Step 3: Perform the subtraction by subtracting numerators.
- .
Step 4: Verify if simplification is necessary.
- The fraction is already in its simplest form.
Therefore, the solution to is .
Solve the following exercise:
\( \frac{1}{3}-\frac{1}{6}=\text{?} \)
Solve the following exercise:
\( \frac{2}{3}-\frac{2}{9}=\text{?} \)
Solve the following exercise:
\( \frac{5}{8}-\frac{1}{4}=\text{?} \)
Solve the following exercise:
To solve this fraction subtraction problem, we need to follow these steps:
Therefore, the solution to is .
Solve the following exercise:
To solve the subtraction of fractions , we will follow a step-by-step approach:
Thus, the result of the subtraction is .
Therefore, the solution to the problem is .
Solve the following exercise:
To solve the problem , we need to follow these steps:
Thus, the result of the subtraction is .
Therefore, the solution to the problem is .