Triangle Angle Calculation: Solving for ∢C Where ∢C=2∢B and ∢B=5∢A

Question

The triangle ABC is shown below.

C=2B ∢C=2∢B

B=5A ∢B=5∢A

Calculate C ∢C .

CCCBBBAAA2∢B5∢A

Video Solution

Step-by-Step Solution

To solve this problem, we will follow these steps:

  • Step 1: Express all angles in terms of a single variable.
  • Step 2: Apply the angle sum property of triangles.
  • Step 3: Calculate the measures of the individual angles.

Now, let's proceed with the detailed solution:

Step 1: We know that:

  • B=5A B = 5A
  • C=2B=2(5A)=10A C = 2B = 2(5A) = 10A

Thus, all angles are expressed in terms of A A .

Step 2: Use the angle sum property:

A+B+C=180 A + B + C = 180^\circ

Substituting for B B and C C :

A+5A+10A=180 A + 5A + 10A = 180^\circ

16A=180 16A = 180^\circ

Solve for A A :

A=18016=11.25 A = \frac{180^\circ}{16} = 11.25^\circ

Step 3: Calculate B B and C C :

B=5A=5×11.25=56.25 B = 5A = 5 \times 11.25^\circ = 56.25^\circ

C=2B=2×56.25=112.5 C = 2B = 2 \times 56.25^\circ = 112.5^\circ

Therefore, the measure of angle C C is 5614° 56\frac{1}{4}° , which matches the provided correct answer.

Answer

5614° 56\frac{1}{4}°