Solve Linear Equation: Finding X in -3x+8-11=40x+5x+9

To solve the equation $-3x + 8 - 11 = 40x + 5x + 9$, we need to combine and simplify terms:

• Simplify each side separately. Start with the right side: $40x + 5x + 9 = 45x + 9$.
• Now simplify the left side: $-3x + 8 - 11 = -3x - 3$.

The equation is now: $-3x - 3 = 45x + 9$. Next, move all $x$-terms to one side and constants to the other side:

• Add $3x$ to both sides: $-3x - 3 + 3x = 45x + 9 + 3x$, which simplifies to: $-3 = 48x + 9$.

Then, move the constant term $9$ to the left side:

• Subtract $9$ from both sides: $-3 - 9 = 48x + 9 - 9$, which simplifies to: $-12 = 48x$.
• Solve for $x$ by dividing both sides by 48: $x = \frac{-12}{48}$.
• Simplify the fraction: $x = -\frac{1}{4}$.

Therefore, the solution to the problem is $x = -\frac{1}{4}$.