Solve the Linear Equation: 5x-4·3+4x+3x=0

Question

5x43+4x+3x=0 5x-4\cdot3+4x+3x=0

Video Solution

Solution Steps

00:00 Solve
00:05 Always solve multiplication and division before addition and subtraction
00:18 Group terms
00:22 We want to isolate the unknown X
00:25 Arrange the equation so that one side has only the unknown X
00:33 Isolate the unknown X, and calculate
00:45 And this is the solution to the question

Step-by-Step Solution

To solve this linear equation 5x43+4x+3x=0 5x - 4 \cdot 3 + 4x + 3x = 0 , follow these steps:

  • Simplify the expression: First, calculate the product 43 4 \cdot 3 . This equals 12 12 .

  • Substitute back into the equation: 5x12+4x+3x=0 5x - 12 + 4x + 3x = 0 .

  • Combine like terms:

    • The terms involving x x are 5x 5x , 4x 4x , and 3x 3x . Add these together: 5x+4x+3x=12x 5x + 4x + 3x = 12x .

  • The equation now simplifies to 12x12=0 12x - 12 = 0 .

  • Isolate x x : Add 12 12 to both sides of the equation to eliminate the constant term on the left:

    • 12x12+12=0+12 12x - 12 + 12 = 0 + 12 , which simplifies to 12x=12 12x = 12 .

  • Solve for x x : Divide both sides by 12 12 to solve for x x :

    • x=1212=1 x = \frac{12}{12} = 1 .

The solution to the equation is x=1 x = 1 .

Verify with the given choices, we find that the correct answer is: x=1 x = 1 .

Answer

x=1 x=1