Solve for Weight Distribution: Finding Orange Quantities in Two Boxes with 61½ kg Total

Question

Jose picked oranges. The total weight of the oranges Jose picked is 6112 61\frac{1}{2} kilograms.

In the red box there are 5kg of oranges more than in the blue box.

How many oranges are in each box?

Step-by-Step Solution

To solve this problem, follow these steps:

  • Define the variables: Let xx be the weight of oranges in the blue box.

  • Set up the equation: Since the red box has 5 kg more than the blue box, its weight is x+5x + 5. The total weight of the two boxes is given as 611261 \frac{1}{2} kg. Thus, the equation is:

x+(x+5)=6112x + (x + 5) = 61 \frac{1}{2}

Now, simplify and solve the equation step by step:

  • Combine like terms: 2x+5=61122x + 5 = 61 \frac{1}{2}

  • Convert the mixed number to an improper fraction for easier calculations: 6112=123261 \frac{1}{2} = \frac{123}{2}

  • Write the equation with the fraction: 2x+5=12322x + 5 = \frac{123}{2}

  • Subtract 5 from both sides: 2x=123252x = \frac{123}{2} - 5

  • Convert 5 to a fraction with the same denominator: 5=1025 = \frac{10}{2}

  • Subtract the fractions: 2x=1232102=11322x = \frac{123}{2} - \frac{10}{2} = \frac{113}{2}

  • Divide both sides by 2 to solve for xx: x=1132÷2=1134x = \frac{113}{2} \div 2 = \frac{113}{4}

Thus, the weight of oranges in the blue box is x=1134=2814x = \frac{113}{4} = 28 \frac{1}{4} kg.

The red box's oranges weigh x+5=1134+204=1334=3314x + 5 = \frac{113}{4} + \frac{20}{4} = \frac{133}{4} = 33 \frac{1}{4} kg.

Therefore, the solution is:

blue box 2814 28\frac{1}{4} red box 3314 33\frac{1}{4}

Answer

blue box 2814 28\frac{1}{4} red box 3314 33\frac{1}{4}