Find the Function Equation Passing Through Point (7,9): Positive Function Analysis

Given a function that is positive from the beginning of the axes. Plus the point (7,9) on the graph of the function. Find the equation for the function.

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Step-by-step video solution

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00:00 Find the function equations
00:03 Points where the function passes according to the given data
00:09 We'll use the line equations
00:17 We'll substitute the point to find the unknown value B
00:33 This is the value of B
00:41 Now we'll substitute the second point to find the slope M
00:59 We'll isolate M
01:07 This is the function's slope
01:16 Now we'll substitute appropriate values to find the function equation
01:31 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

Given a function that is positive from the beginning of the axes. Plus the point (7,9) on the graph of the function. Find the equation for the function.

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the given information

  • Step 2: Calculate the slope of the line passing through the origin and the point (7, 9)

  • Step 3: Write the equation of the line that represents the function

Now, let's work through each step:
Step 1: We have the point (7, 9) and know the function is positive starting from the origin, suggesting a line through the origin.

Step 2: Calculate the slope m m :
Using the points (0, 0) and (7, 9), apply the slope formula m=y2y1x2x1 m = \frac{y_2 - y_1}{x_2 - x_1} :

m=9070=97\quad m = \frac{9 - 0}{7 - 0} = \frac{9}{7}

Step 3: Write the equation of the line:
Since the line passes through the origin, the form is y=mx y = mx , so:

y=97x\quad y = \frac{9}{7}x

Therefore, the function equation is y=127x y = 1\frac{2}{7}x .

3

Final Answer

y=127x y=1\frac{2}{7}x

Practice Quiz

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Look at the function shown in the figure.

When is the function positive?

xy-4-7

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