Applying Combined Exponents Rules: Using variables

$a^{-4}=\text{?}$

$(a\ne0)$

We begin by using the negative exponent rule.

$b^{-n}=\frac{1}{b^n}$We apply it to the problem:

$$$$$a^{-4}=\frac{1}{a^4}$Therefore, the correct answer is option B.

$\frac{1}{a^4}$

$x^{-a}=\text{?}$

We use the exponential property of a negative exponent:

$b^{-n}=\frac{1}{b^n}$We apply it to the problem:

$$$x^{-a}=\frac{1}{x^a}$Therefore, the correct answer is option C.

$\frac{1}{x^a}$

$\frac{1}{a^n}=\text{?}$

$a\ne0$

$a^{-n}$$$

$8^{-2x}=\text{?}$

$\frac{1}{64^x}$