Power in logarithm

In order to solve a logarithm that appears in an exponent, you need to know all logarithm rules including the sum of logarithms, product of logarithms, change of base rule, etc.

Solution steps:

  1. Take the logarithm with the same base on both sides of the equation.
    The base will be the original base - the one on which the log power is applied.
  2. Use the rule
    loga(ax)=xlog_a (a^x)=x
  3. Create a common base between the 22 equation factors to reach a solution.
  4. Solve the logs that can be solved and convert them to numbers.
  5. Substitute an auxiliary variable TT if needed
  6. Go back to find XX.

Suggested Topics to Practice in Advance

  1. Addition of Logarithms

Practice Power Property of Logorithms

Examples with solutions for Power Property of Logorithms

Exercise #1

2log38= 2\log_38=

Video Solution

Answer

log364 \log_364

Exercise #2

3log76= 3\log_76=

Video Solution

Answer

log7216 \log_7216

Exercise #3

log68= \log_68=

Video Solution

Answer

3log62 3\log_62

Exercise #4

xln7= x\ln7=

Video Solution

Answer

ln7x \ln7^x

Exercise #5

7\log_42<\log_4x

Video Solution

Answer

2^7 < x

Exercise #6

nlogxa= n\log_xa=

Video Solution

Answer

logxan \log_xa^n

Exercise #7

Solve for X:

log3(x+2)log29=4 \log_3(x+2)\cdot\log_29=4

Video Solution

Answer

2 2

Exercise #8

xlogm13x= x\log_m\frac{1}{3^x}=

Video Solution

Answer

x2logm3 -x^2\log_m3

Exercise #9

Calculate X:

2log(x+4)=1 2\log(x+4)=1

Video Solution

Answer

4+10 -4+\sqrt{10}

Exercise #10

12log3(x4)=log3(3x2+5x+1) \frac{1}{2}\log_3(x^4)=\log_3(3x^2+5x+1)

x=? x=\text{?}

Video Solution

Answer

54±174 -\frac{5}{4}\pm\frac{\sqrt{17}}{4}

Exercise #11

2log(x+1)=log(2x2+8x) 2\log(x+1)=\log(2x^2+8x)

x=? x=\text{?}

Video Solution

Answer

3+10 -3+\sqrt{10}

Exercise #12

log45+log423log42= \frac{\log_45+\log_42}{3\log_42}=

Video Solution

Answer

log810 \log_810

Exercise #13

log35x×log179log174 \log_35x\times\log_{\frac{1}{7}}9\ge\log_{\frac{1}{7}}4

Video Solution

Answer

0 < x\le\frac{1}{245}

Exercise #14

log311log34+1ln32log3= \frac{\log_311}{\log_34}+\frac{1}{\ln3}\cdot2\log3=

Video Solution

Answer

log411+loge2 \log_411+\log e^2

Exercise #15

2log78log74+1log43×log29= \frac{2\log_78}{\log_74}+\frac{1}{\log_43}\times\log_29=

Video Solution

Answer

7 7