In order to solve a logarithm that appears in an exponent, you need to know all logarithm rules including the sum of logarithms, product of logarithms, change of base rule, etc.
In order to solve a logarithm that appears in an exponent, you need to know all logarithm rules including the sum of logarithms, product of logarithms, change of base rule, etc.
Solution steps:
\( 2\log_38= \)
\( 3\log_76= \)
\( \log_68= \)
\( x\ln7= \)
\( 7\log_42<\log_4x \)
7\log_42<\log_4x
2^7 < x
\( n\log_xa= \)
Solve for X:
\( \log_3(x+2)\cdot\log_29=4 \)
\( x\log_m\frac{1}{3^x}= \)
Calculate X:
\( 2\log(x+4)=1 \)
\( \frac{1}{2}\log_3(x^4)=\log_3(3x^2+5x+1) \)
\( x=\text{?} \)
Solve for X:
Calculate X:
\( 2\log(x+1)=\log(2x^2+8x) \)
\( x=\text{?} \)
\( \frac{\log_45+\log_42}{3\log_42}= \)
\( \log_35x\times\log_{\frac{1}{7}}9\ge\log_{\frac{1}{7}}4 \)
\( \frac{\log_311}{\log_34}+\frac{1}{\ln3}\cdot2\log3= \)
\( \frac{2\log_78}{\log_74}+\frac{1}{\log_43}\times\log_29= \)
0 < x\le\frac{1}{245}