Power Property of Logorithms: Using variables

$x\ln7=$

$\ln7^x$

$n\log_xa=$

$\log_xa^n$

Solve for X:

$\log_3(x+2)\cdot\log_29=4$

$2$

$x\log_m\frac{1}{3^x}=$

$-x^2\log_m3$

Calculate X:

$2\log(x+4)=1$

$-4+\sqrt{10}$

$\frac{1}{2}\log_3(x^4)=\log_3(3x^2+5x+1)$

$x=\text{?}$

$-\frac{5}{4}\pm\frac{\sqrt{17}}{4}$

$2\log(x+1)=\log(2x^2+8x)$

$x=\text{?}$

$-3+\sqrt{10}$

$\frac{\log_47\times\log_{\frac{1}{49}}a}{c\log_4b}=$

$\log_{b^c}\frac{1}{\sqrt{a}}$

$\log_x16\times\frac{\ln7-\ln x}{\ln4}-\log_x49=$

$-2$

$(2\log_32+\log_3x)\log_23-\log_2x=3x-7$

$x=\text{?}$

$3$

$\frac{\log_x4+\log_x30.25}{x\log_x11}+x=3$

$x=\text{?}$

$2$

$\frac{1}{\log_{2x}6}\times\log_236=\frac{\log_5(x+5)}{\log_52}$

$x=\text{?}$

$1.25$

Find X

$\frac{1}{\log_{x^4}2}\times x\log_x16+4x^2=7x+2$

$\frac{-9+\sqrt{113}}{8}$