Addition, Subtraction, Multiplication and Division: Addition, subtraction, multiplication and division

According to the rules of the order of operations, multiplication and division precede addition and subtraction.

We isolate the multiplication exercise in parentheses and solve.

$(7\times3)=21$

Now, the exercise we're left with is: $21+8-4-7=$

We solve the exercise from left to right. We isolate the next part of the expression with parentheses to avoid confusion$(21+8)=29$

Now, the exercise obtained is: $29-4-7=$

We continue solving from left to right and isolate the next part of the expression in parentheses.

$(29-4)=25$

Now, the expression obtained is: $25-7=18$

According to the rules of the order of operations, we first solve the multiplication exercise:

$3+8+(4\times3)=$

$4\times3=12$

Now, we solve the addition exercise from left to right:

$3+8+12=$

$11+12=23$

According to the order of operations, we put the multiplication and division exercise in parentheses:

$(15:5)+(4\times3)=$

Now we solve the parentheses:

$15:5=3$

$4\times3=12$

And we get the exercise:

$3+12=15$

According to the order of operations, we place the multiplication and division exercise within parentheses:

$(20:4)+(3\times2)=$

Now we solve the exercises within parentheses:

$20:4=5$

$3\times2=6$

And we obtain the exercise:

$5+6=11$

According to the rules of the order of arithmetic operations, we must first enclose both the multiplication and division exercises inside of parentheses:

$1+(2\times3)-(7:4)=$

We then solve the exercises within the parentheses:

$2\times3=6$

$7:4=\frac{7}{4}$

We obtain the following:

$1+6-\frac{7}{4}=$

We continue by solving the exercise from left to right:

$1+6=7$

$7-\frac{7}{4}=$

Lastly we break down the numerator of the fraction with a sum exercise as seen below:

$7-(\frac{4+3}{4})$

$7-(\frac{4}{4}+\frac{3}{4})$

$7-(1+\frac{3}{4})$

$7-1\frac{3}{4}=5\frac{1}{4}$

According to the rules of the order of arithmetic operations, we begin by enclosing the multiplication exercise inside parentheses:

$2-(5\times3)+4=$

We then solve the said exercise inside of the parentheses:

$5\times3=15$

We obtain the following:

$2-15+4=$

Lastly we solve the exercise from left to right:

$2-15=-13$

$-13+4=-9$

According to the order of operations rules, we first insert the multiplication and division exercises into parentheses:

$2+(4\times5:2)+3=$

Now let's solve the expression in parentheses from left to right:

$4\times5=20$

$20:2=10$

And we get the expression:

$2+10+3=$

Let's solve the expression from left to right:

$2+10=12$

$12+3=15$

According to the order of arithmetic operations, multiplication and division precede addition and subtraction,

Therefore, let's start first with the division operation:

$3+10-(2:4)+1=3+10-\frac{1}{2}+1$

Now, as all remaining operations are at the same level (addition and subtraction),

let's start solving from left to right:

$3+10-\frac{1}{2}+1=13-\frac{1}{2}+1$

$13-\frac{1}{2}+1=12\frac{1}{2}+1=13\frac{1}{2}$

According to the rules of the order of arithmetic operations, we must first solve the multiplication exercises.

We place them inside of parentheses to avoid confusion during the solution:

$4-(5\times7)+3=$

We then solve the multiplication exercises:

$4-35+3=$

Lastly we solve the rest of the exercise from left to right:

$4-35=-31$

$-31+3=-28$

According to the rules of the order of arithmetic operations, we must first place the multiplication and division exercises within parentheses:

$2-(6:2)+(5\times2)=$

We then solve the exercise inside of the parentheses:

$6:2=3$

$5\times2=10$

We obtain the following exercise:

$2-3+10=$

Finally we solve the exercise from left to right:

$2-3=-1$

$-1+10=9$

According to the rules of the order of arithmetic operations, we must first place multiplication and division exercises inside of parentheses:

$2+3-(15:3\times4)+6=$

We then solve the exercise within the parentheses from left to right:

$15:3=5$

$5\times4=20$

After which we are left with the following exercise:

$2+3-20+6=$

Lastly we solve the exercise from left to right:

$2+3=5$

$5-20=-15$

$-15+6=-9$

According to the rules of the order of operations, we solve the exercise from left to right since the exercise only involves multiplication and division:

$80:10=8$

$8:5=\frac{8}{5}$

$\frac{8}{5}\times5=8$

$8:25=\frac{8}{25}$

Let's start with the part inside the parentheses. 

$2+2=4$
Then we will solve the exercise from left to right 

$8:2=4$
$4 × (4)=16$

The answer: $16$

According to the order of operations, we place the multiplication and division exercise in parentheses:

$(12:4)-3+(3\times3)=$

We solve the exercises in parentheses:

$12:4=3$

$3\times3=9$

And we obtain the exercise:

$3-3+9=$

According to the order of operations, we solve the exercise from left to right:

$3-3=0$

$0+9=9$

According to the order of operations, we place the multiplication and division exercise within parentheses:

$(9:3)-(1.5\times2)=$

Now we solve the exercises within parentheses:

$9:3=3$

$1.5\times2=3$

And we obtain the exercise:

$3-3=0$

According to the order of operations rules, we first insert the multiplication and division exercises into parentheses:

$3+(4:2\times1)-9+4=$

We'll solve the exercise from left to right:

$4:2=2$

$2\times1=2$

And we'll get the exercise:

$3+2-9+4=$

Since the exercise only contains subtraction operations, we'll solve it from left to right:

$3+2=5$

$5-9=-4$

$-4+4=0$

According to the rules of the order of arithmetic operations, we will begin by enclosing the multiplication and division exercises inside of parentheses:

$(25:5)+(4\times3)-5=$

We then proceed to solve the exercises in the parentheses:

$25:5=5$

$4\times3=12$

We obtain the following:

$5+12-5=$

To finish we solve the exercise from left to right:

$5+12=17$

$17-5=12$

According to the rules of the order of arithmetic operations, we must first place the multiplication and division exercises inside of parentheses:

$7+(21:7\times4)+3-9=$

We then proceed to solve the exercise inside of the parentheses from left to right:

$21:7=3$

$3\times4=12$

Which results in the following exercise:

$7+12+3-9=$

We then finish by solving the exercise from left to right:

$7+12=19$

$19+3=22$

$22-9=13$

According to the rules of the order of arithmetic operations, we must first solve the multiplication exercises.

We place them inside of parentheses in order to avoid confusion during the solution:

$2+(3\times6)-(3\times7)+1=$

We then solve the multiplication exercises:

$2+18-21+1=$

Lastly we solve the rest of the exercise from left to right:

$2+18=20$

$20-21=-1$

$-1+1=0$

According to the rules of the order of arithmetic operations, we begin by placing the multiplication and division exercises inside of parentheses:

$8+(3\times4)-2+1=$

We then solve the exercise within the parentheses:

$3\times4=12$

We obtain the following :

$8+12-2+1=$

Finally we solve the exercise from left to right:

$8+12=20$

$20-2=18$

$18+1=19$