Addition, Subtraction, Multiplication and Division: Solving the problem

According to the order of operations, solve the exercise from left to right since the only operations in it are addition and subtraction:

$10-3=7$

$7+7=14$

$14-5=9$

According to the order of operations, we will solve the exercise from left to right since the only operations in it are addition and subtraction:

$90-2=88$

$88+9=97$

$97-8=89$

Due to the fact that the exercise only involves addition and subtraction operations, we will solve it from left to right:

$12+6=18$

$18-4=14$

$14+18=32$

$32-12=20$

Due to the fact that the exercise only involves addition and subtraction operations, we will solve it from left to right:

$14-5=9$

$9-9=0$

$0+7=7$

$7+2=9$

Due to the fact that the exercise only involves addition and subtraction operations, we will solve it from left to right:

$21-3=18$

$18-6=12$

$12+9=21$

$21-5=16$

Due to the fact that the exercise only involves addition and subtraction operations, we will solve it from left to right:

$25-6=19$

$19-9=10$

$10+7=17$

$17-3=14$

Due to the fact that the exercise only involves addition and subtraction operations, we will solve it from left to right:

$25+6=31$

$31-19=12$

$12+7=19$

Due to the fact that the exercise only involves addition and subtraction operations, we will solve it from left to right:

$26-6=20$

$20+9=29$

$29+7=36$

$36-12=24$

Due to the fact that the exercise only involves addition and subtraction operations, we will solve it from left to right:

$32-4=28$

$28-19=9$

$9+3=12$

$12-7=5$

Insofar as the exercise only involves addition and subtraction operations, we will solve it from left to right:

$30+6=36$

$36-5=31$

$31+7=38$

$38-17=21$

According to the order of operations, we first put the multiplication exercise in parentheses to avoid confusion in the rest of the solution:

$(25\times6)-9-41=$

Let's solve the multiplication exercise first:

$150-9-41=$

Now let's solve the exercise from left to right:

$150-9=141$

$141-41=100$

According to the rules of the order of operations, the exercise which contains both multiplication and division should be solved from left to right.

$30:5=6$

$6\times2=12$

The division and multiplication have the same priority according to the order of operations, therefore we solve it from left to right:

$10\cdot2=20$

$20/4=5$

According to the order of operations rules, we first enter the multiplication and division exercises into parentheses:

$(5\times5\times2)-(12:4)=$

Now let's solve the exercises in parentheses from left to right:

$5\times5=25$

$25\times2=50$

$12:4=3$

We obtain the following exercise:

$50-3=47$

According to the order of operations rules, we first insert the multiplication and division exercises into parentheses:

$(24:2)-4-(3:3)=$

Let's solve the exercises in parentheses:

$24:2=12$

$3:3=1$

Now we have the expression:

$12-4-1=$

Let's solve the expression from left to right:

$12-4=8$

$8-1=7$

According to the order of operations, we will first solve the multiplication exercises.

We will put them in parentheses so that we don't get confused later in the solution:

$25-(3\times4)+(4\times2)=$

Let's solve the multiplication exercises:

$3\times4=12$

$4\times2=8$

We get:

$25-12+8=$

Let's solve the exercise from left to right:

$25-12=13$

$13+8=21$

According to the rules of the order of operations we should first solve the exercise from left to right since it only contains a division operation:

$80:4=20$

$20:2=10$

$10:5=2$

According to the order of operations rules, we first enter the multiplication and division operations into parentheses:

$(100:2)-(10:2)+(3\times4)-6-(5\times2)=$

Now let's solve the operations within the parentheses:

$100:2=50$

$10:2=5$

$3\times4=12$

$5\times2=10$

We obtain the following expression:

$50-5+12-6-10=$

Let's solve the expression from left to right:

$50-5=45$

$45+12=57$

$57-6=51$

$51-10=41$