Solve (12-15÷3×2)/(10÷(2+3)): Order of Operations Challenge

$\frac{12-15:3\cdot2}{10:(2+3)}=$

We start by solving the exercise in the numerator and then solve the exercise in the denominator.

We know that multiplication and division operations come before addition and subtraction operations, so first we will divide 15:3 and then multiply the result by 2:

$15:3=5$

$12-5\times2=12-10=2$

The result of the numerator is 2 and now we will solve the exercise that appears in the denominator.

It is known that according to the rules of the order of operations, the exercise that appears between parentheses goes first, so we first solve the exercise$2+3=5$

$$Now, we solve the division exercise:$10:5=2$

The result we get in the denominator is 2.

Finally, divide the numerator by the denominator:

$\frac{2}{2}=1$