Examples with solutions for Addition, Subtraction, Multiplication and Division: Complete the missing numbers

Exercise #1

What is the missing number?

23−12×(−6)+? ⁣:7=102 23-12\times(-6)+\red{\boxed{?}}\colon7=102

Video Solution

Step-by-Step Solution

First, we solve the multiplication exercise:

12×(−6)=−72 12\times(-6)=-72

Now we get:

23−(−72)+x ⁣:7=102 23-(-72)+x\colon7=102

Let's pay attention to the minus signs, remember that a negative times a negative equals a positive.

We multiply them one by one to be able to open the parentheses:

23+72+x ⁣:7=102 23+72+x\colon7=102

We reduce:

95+x:7=102 95+x:7=102

We move the sections:

x:7=102−95 x:7=102-95

x:7=7 x:7=7

x7=7 \frac{x}{7}=7

Multiply by 7:

x=7×7=49 x=7\times7=49

Answer

49

Exercise #2

9+?+3=25 9+?+3=25

Video Solution

Step-by-Step Solution

To find out which number is missing, we solve the entire exercise to know which number we will have to add to obtain a result of 25:

9+3=12 9+3=12

To make 12 equal to 25 we will have to add the number 13.

Let's verify:

25−12=13 25-12=13

Answer

13 13

Exercise #3

7+?+2=20 7+?+2=20

Video Solution

Step-by-Step Solution

To find out which number is missing, we solve the entire exercise to know which number we will have to add to obtain a result of 20:

7+2=9 7+2=9

To make 9 equal to 20 we will have to add the number 11.

Let's verify:

20−9=11 20-9=11

Answer

11 11

Exercise #4

9+?−3=25 9+?-3=25

Video Solution

Step-by-Step Solution

To find out which number is missing, we solve the entire exercise to know which number we will have to add to get a result of 25:

9−3=6 9-3=6

To make 6 equal to 25 we will have to add 19.

Let's verify:

25−6=19 25-6=19

Answer

19 19

Exercise #5

12+?+3−1=29 12+?+3-1=29

Video Solution

Step-by-Step Solution

To find out which number is missing, we solve the entire exercise to know which number we will have to add to obtain a result of 29:

12+3−1= 12+3-1=

15−1=14 15-1=14

To make 14 equal to 29, we will have to add 15.

Let's verify:

29−14=15 29-14=15

Answer

15 15

Exercise #6

17−?+4=5 17-?+4=5

Video Solution

Step-by-Step Solution

The question mark is the unknown, so we will refer to the exercise as an equation.

We arrange the exercise to isolate the question mark:

17+4−?=5 17+4-?=5

We reduce:

21−?=5 21-?=5

We move to thevariable to the other side and change to the correct sign:

21=?+5 21=?+5

We move the 5 to the other side and change to the correct sign: 21−5=? 21-5=\text{?}

16=? 16=\text{?}

Answer

16 16

Exercise #7

7−?+4+2×18=29 7-?+4+2\times18=29

Video Solution

Step-by-Step Solution

First, we place the multiplication exercise in parentheses:

7−?+4+(2×18)=29 7-?+4+(2\times18)=29

We solve the exercise in parentheses:

2×18=36 2\times18=36

Now we obtain the exercise:

7−?+4+36=29 7-?+4+36=29

We reduce the addition exercise:

36+4=40 36+4=40

Now we obtain the exercise:

7−?+40=29 7-?+40=29

The question mark is the unknown, therefore we will refer to the exercise as an equation.

We arrange the exercise to isolate the question mark:

40+7−?=29 40+7-?=29

We reduce:

47−?=29 47-?=29

We move 47 to the other side and change to the correct sign:

−?=29−47 -?=29-47

−?=−18 -?=-18

We divide both sides by -1 to change to the correct sign:

?=18 ?=18

Answer

18 18

Exercise #8

12×3−4+?=27 12\times3-4+?=27

Video Solution

Step-by-Step Solution

According to the rules of operations, we first place the multiplication exercise in parentheses:

(12×3)−4+?=27 (12\times3)-4+?=27

We solve the exercise in parentheses:

12×3=36 12\times3=36

We obtain the exercise:

36−4+?=27 36-4+?=27

We reduce:

32+?=27 32+?=27

We move 32 to the other side and change to the correct sign:

?=27−32 ?=27-32

?=−5 ?=-5

Answer

−5 -5

Exercise #9

8×7−3+?=60 8\times7-3+?=60

Video Solution

Step-by-Step Solution

According to the rules of operations, we first place the multiplication exercise in parentheses:

(8×7)−3+?=60 (8\times7)-3+?=60

8×7=56 8\times7=56

Now we obtain the exercise:

56−3+?=60 56-3+?=60

We reduce the subtraction exercise:

56−3=53 56-3=53

We obtain the exercise:

53+?=60 53+?=60

We move 53 to the other side and change to the correct sign:

?=60−53 ?=60-53

?=7 ?=7

Answer

7 7

Exercise #10

12×3−4×?=12 12\times3-4\times?=12

Video Solution

Step-by-Step Solution

According to the laws of Arithmetic operations:

We must first place the multiplication exercise inside parentheses as shown below:(12×3)−4×?=12 (12\times3)-4\times?=12

We then solve the multiplication:

12×3=36 12\times3=36

Which should result in the following calculation:

36−4×?=12 36-4\times?=12

We then transfer numbers to the other side of the equation and change the signs accordingly:

−4×?=12−36 -4\times?=12-36

We complete the subtraction exercise:

12−36=−24 12-36=-24

Resulting in the following calculation:

−4×?=−24 -4\times?=-24

Finally we divide by negative 4:

?=−24−4 ?=\frac{-24}{-4}

?=6 ?=6

Answer

6 6

Exercise #11

−5×−7+?=48−11 -5\times-7+?=48-11

Video Solution

Step-by-Step Solution

According to the order of operations rules, we first enter the multiplication problem inside the parentheses:

(−5×−7)+?=48−11 (-5\times-7)+?=48-11

We solve the problem inside the parentheses and the subtraction problem:

−5×−7=35 -5\times-7=35

48−11=37 48-11=37

Now we get the problem:

35+?=37 35+?=37

We move the term and change the sign accordingly:

?=37−35 ?=37-35

?=2 ?=2

Answer

2 2