Zeros of a Fuction - Examples, Exercises and Solutions

Determine the points of intersection of the function

$y=(x-5)(x+5)$

With the X

In order to find the point of the intersection with the X-axis, we first need to establish that Y=0.

0 = (x-5)(x+5)

When we have an equation of this type, we know that one of these parentheses must be equal to 0, so we begin by checking the possible options.

x-5 = 0
x = 5

x+5 = 0
x = -5

That is, we have two points of intersection with the x-axis, when we discover their x points, and the y point is already known to us (0, as we placed it):

(5,0)(-5,0)

This is the solution!

$(5,0),(-5,0)$

The following function has been graphed below:

$f(x)=-x^2+5x+6$

Calculate points A and B.

$(-1,0),(6,0)$

The following function has been graphed below:

$f(x)=x^2-6x+5$

Calculate points A and B.

$$

$(1,0),(5,0)$

The following function has been graphed below:

$f(x)=x^2-8x+16$

Calculate point A.

$(0,16)$

The following function has been graphed below:

$f(x)=x^2-8x+16$

Calculate point C.

$(4,0)$

The following function has been graphed below:

$f(x)=x^2-3x-4$

Calculate points A and B.

$A(-1,0),B(4,0)$

The following function has been graphed below:

$f(x)=x^2-6x$

Calculate points A and B.

$(6,0),\lparen0,0)$

The following function has been graphed below:

$f(x)=x^2-6x+8$

Calculate points A and B.

$(2,0),(4,0)$

Determine the points of intersection of the function

$y=(x-2)(x+3)$

With the X

$(-3,0),(2,0)$

Determine the points of intersection of the function

$y=(x-1)(x+10)$

With the X

$(1,0),(-10,0)$

Determine the points of intersection of the function

$y=(x-3)(x+3)$

With the X

$(-3,0),(3,0)$

Determine the points of intersection of the function

$y=x(x+5)$

With the X

$(-5,0),(0,0)$

Determine the points of intersection of the function

$y=(x+7)(x+2)$

With the X

$(-2,0),(-7,0)$

Determine the points of intersection of the function

$y=(x+3)(x-3)$

With the X

$(3,0),(-3,0)$

Determine the points of intersection of the function

$y=(x-11)(x+1)$

With the X

$(-1,0),(11,0)$