Solve the exercise:
84:4=
Solve the exercise:
84:4=
Solve the following exercise
?=24:12
Solve the following exercise
?=93:3
Solve the following exercise
=90:5
Solve:
\( 72:6= \)
Solve the exercise:
84:4=
There are several ways to solve the following exercise,
We will present two of them.
In both ways, we begin by decomposing the number 84 into smaller units; 80 and 4.
Subsequently we are left with only the 80.
Continuing on with the first method, we will then further decompose 80 into smaller units;
We know that:
And therefore, we are able to reduce the exercise as follows:
Eventually we are left with
which is equal to 20
In the second method, we decompose 80 into the following smaller units:
We know that:
And therefore:
which is also equal to 20
Now, let's remember the 1 from the first step and add it in to our above answer:
Thus we are left with the following solution:
21
Solve the following exercise
?=24:12
We will use the distributive property of division and split the number 24 into a sum of 12 and 12, which makes the division operation easier and allows us to solve the exercise without a calculator.
Note - it's best to choose to split the number based on knowledge of multiples. In this case of the number 12 because we need to divide by 12.
Reminder - The distributive property of division actually allows us to split the larger term in a division problem into a sum or difference of smaller numbers, which makes the division operation easier and allows us to solve the exercise without a calculator
We will use the formula of the distributive property
Therefore the answer is section a - 2.
2
Solve the following exercise
?=93:3
We will use the distributive property of division and split the number 93 into a sum of 90 and 3, which makes the division operation easier and allows us to solve the exercise without a calculator.
Note - it's best to choose to split the number based on knowledge of multiples. In this case, we use 3 because we need to divide by 3. Additionally, in this case, splitting by tens and ones is suitable and makes the division operation easier.
Reminder - The distributive property of division essentially allows us to split the larger term in the division problem into a sum or difference of smaller numbers, which makes the division operation easier and allows us to solve the exercise without a calculator
We will use the formula of the distributive property
Therefore, the answer is option B - 31.
31
Solve the following exercise
=90:5
We use the distributive property of division to separate the number 90 between the sum of 50 and 40, which facilitates the division and gives us the possibility to solve the exercise without a calculator.
Keep in mind: it is beneficial to choose to split the number according to your knowledge of multiples. In this case into multiples of 5, because it is necessary to divide by 5.
Reminder: the distributive property of division actually allows us to separate the larger term in a division exercise into the sum or the difference of smaller numbers, which facilitates the division operation and gives us the possibility to solve the exercise without a using calculator.
We use the formula of the distributive property
(a+b):c=a:c+b:c
Therefore, the answer is option c: 18
18
Solve:
We will use the distributive property of division and split the number 72 into a sum of 60 and 12, which makes the division operation easier and allows us to solve the exercise without a calculator.
Note - it's best to choose to split the number based on knowledge of multiples. In this case of the digit 6 because we need to divide by 6.
Note - splitting according to multiples of the dividing digit (in this case 6) by 10 matches and makes the division operation easier.
Reminder - The distributive property of division actually allows us to split the larger term in the division exercise into a sum or difference of smaller numbers, which makes the division operation easier and gives us the ability to solve the exercise without a calculator
We will use the formula of the distributive property
Therefore the answer is option C - 12.
12
Solve the exercise:
=102:2
\( 4\times53= \)
\( 11\times34= \)
\( 6\times29= \)
\( 30\times39= \)
Solve the exercise:
=102:2
We will use the distributive property of division and split the number 102 into a sum of 100 and 2, which makes the division operation easier and allows us to solve the exercise without a calculator.
Note - it's best to choose to split the number based on knowledge of multiples. In this case of the digit 2 because we need to divide by 2. Additionally, in this case, splitting by tens and ones is suitable and makes the division operation easier.
Reminder - The distributive property of division essentially allows us to split the larger term in the division problem into a sum or difference of smaller numbers, which makes the division operation easier and gives us the ability to solve the exercise without a calculator
We will use the formula of the distributive property
Therefore the answer is section a - 51.
51
To make solving easier, we break down 53 into more comfortable numbers, preferably round ones.
We obtain:
We multiply 2 by each of the terms inside the parentheses:
We solve the exercises inside the parentheses and obtain:
212
To make solving easier, we break down 11 into more comfortable numbers, preferably round ones.
We obtain:
We multiply 34 by each of the terms in parentheses:
We solve the exercises in parentheses and obtain:
374
To make solving easier, we break down 29 into more comfortable numbers, preferably round ones.
We obtain:
We multiply 6 by each of the terms in parentheses:
We solve the exercises in parentheses and obtain:
174
To solving easier, we break down 39 into more convenient numbers, preferably round ones.
We obtain:
We multiply 30 by each of the terms in parentheses:
We solve the exercises in parentheses and obtain:
1170
\( 3\times93= \)
\( \)\( 3\times56= \)
\( 9\times33= \)
Solve the exercise:
=72:18
\( 3\times560= \)
In order to simplify our calculation, we first break down 93 into smaller, more manageable parts. (Preferably round numbers )
We obtain the following:
We then use the distributive property in order to find the solution.
We multiply each of the terms in parentheses by 3:
Lastly we solve each of the terms in parentheses and obtain:
279
In order to facilitate the resolution process, we break down 56 into an exercise with smaller, preferably round, numbers.
We use the distributive property and multiply each of the terms in parentheses by 3:
We then solve each of the exercises inside of the parentheses and obtain the following result:
168
In order to facilitate the resolution process, we first break down 33 into a smaller addition exercise with more manageable and preferably round numbers:
Using the distributive property we then multiply each of the terms in parentheses by 9:
Finally we solve each of the exercises inside of the parentheses:
297
Solve the exercise:
=72:18
We will use the distributive property of division and split the number 72 into a sum of 36 and 36, which makes the division operation easier and allows us to solve the exercise without a calculator.
Note - it's advisable to split the number according to multiples of the divisor. In this case of the number 18 because we need to divide by 18.
Reminder - The distributive property of division actually allows us to split the larger term in the division problem into a sum or difference of smaller numbers, which makes the division operation easier and allows us to solve the exercise without a calculator
We will use the formula of the distributive property
Therefore the answer is option B - 4.
4
To make solving easier, we break down 560 into more comfortable numbers, preferably round ones.
We obtain:
We multiply 3 by each of the terms in parentheses:
We solve the exercises in parentheses and obtain:
1680
\( 12\times19= \)
\( 18\times69= \)
\( 33\times16= \)
\( 2\times3\times43= \)
\( \)\( 122\times12:4= \)
To make solving easier, let's break down 12 and 19 into more convenient numbers, preferably round numbers.
We get:
We'll use the distributive property to solve.
First, we'll multiply the first term in the left parentheses by the first term in the right parentheses.
We'll multiply the first term in the left parentheses by the second term in the right parentheses.
We'll multiply the second term in the left parentheses by the first term in the right parentheses.
We'll multiply the second term in the left parentheses by the second term in the right parentheses.
We get:
Let's solve what's in the parentheses and we get:
Let's solve from left to right:
228
To make it easier for us to solve, let's break down 12 and 19 into more convenient numbers, preferably round ones.
We get:
We'll use the distributive property to solve.
First, we'll multiply the first term in the left parentheses by the first term in the right parentheses.
We'll multiply the first term in the left parentheses by the second term in the right parentheses.
We'll multiply the second term in the left parentheses by the first term in the right parentheses.
We'll multiply the second term in the left parentheses by the second term in the right parentheses.
We get:
Let's solve what's in the parentheses and we get:
We'll use the associative property and first solve:
Now we get:
Let's solve from left to right:
1242
To make it easier for us to solve, let's break down 33 and 16 into more convenient numbers, preferably round ones.
We get:
We'll use the distributive property to solve.
First, we'll multiply the first term in the left parentheses by the first term in the right parentheses.
We'll multiply the first term in the left parentheses by the second term in the right parentheses.
We'll multiply the second term in the left parentheses by the first term in the right parentheses.
We'll multiply the second term in the left parentheses by the second term in the right parentheses.
We get:
Let's solve what's in the parentheses and we get:
Let's solve from left to right:
528
First, we solve the exercise from left to right.
We apply the associative property in order to simplify the exercise making it easier to solve:
Resulting in the following calculation:
We then decompose 43 into smaller parts rendering the equation easier to solve:
We apply the distributive property in order to solve the equation.
We then multiply 6 by each of the terms inside the parentheses:
Resulting in the following solution:
258
First, we break down 122 into smaller numbers and write the division exercise in the form of a fraction:
We solve the fraction exercise:
We then multiply the terms inside the parentheses by 3 and obtain the following result:
Lastly we solve each of the exercises inside of the parentheses:
366