140−70=
\( 140-70= \)
\( 94+72= \)
\( 133+30= \)
\( 63-36= \)
\( 143-43= \)
In order to simplify the resolution process, we begin by using the distributive property for 140:
We then rearrange the exercise using the substitution property into a more practical form:
Lastly we solve the exercise from left to right:
70
In order to simplify the calculation , we first break down 94 and 72 into smaller and preferably round numbers.
We obtain the following exercise:
Using the associative property, we then rearrange the exercise to be more functional.
We solve the exercise in the following way, first the round numbers and then the small numbers.
Which results in the following exercise:
166
In order to solve the question, we first use the distributive property for 133:
We then use the distributive property for 33:
We rearrange the exercise into a more practical form:
We solve the middle exercise:
Which results in the final exercise as seen below:
163
To solve the problem, first we will use the distributive property on the two numbers:
(60+3)-(30+6)
Now, we will use the substitution property to arrange the exercise in the way that is most convenient for us to solve:
60-30+3-6
It is important to pay attention that when we open the second parentheses, the minus sign moved to the two numbers inside.
30-3 =
27
27
100
\( (7+2+3)(7+6)(12-3-4)=\text{?} \)
780