Examples with solutions for Solving an Equation by Multiplication/ Division: One sided equations

Exercise #1

3xx=8 3x - x = 8

x=? x = \text{?}

Step-by-Step Solution

Start by simplifying the left-hand side of the equation:

3xx=2x 3x - x = 2x

So the equation becomes:

2x=8 2x = 8

To find the value of x x , divide both sides by 2:

x=82 x = \frac{8}{2}

Then simplify the fraction:

x=4 x = 4

Thus, the solution to the equation isx=4 x = 4 .

Answer

4

Exercise #2

4x+2x=18 4x + 2x = 18

Solve the equation above for x x .

Step-by-Step Solution

Combine like terms on the left-hand side:

4x+2x=6x 4x + 2x = 6x

The equation becomes:

6x=18 6x = 18

Divide both sides by 6 to solve for x x :

x=186 x = \frac{18}{6}

Simplify the division:

x=3 x = 3

Thus, x=3 x = 3 is the solution to the equation.

Answer

x=3 x = 3

Exercise #3

x+2x=9 x+2x=9

x=? x=\text{?}

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Combine like terms on the left side of the equation.
  • Solve for x x by isolating it on one side of the equation.

Let's work through the solution:

Step 1: Combine like terms in the equation x+2x=9 x + 2x = 9 . The terms x x and 2x 2x are like terms because they both contain the variable x x . When combined, these terms give us:

x+2x=3x x + 2x = 3x

Step 2: The equation now simplifies to:

3x=9 3x = 9

Step 3: Solve for x x by dividing both sides of the equation by 3 to isolate x x :

x=93 x = \frac{9}{3}

The calculation gives us:

x=3 x = 3

Therefore, the solution to the problem is x=3 x = 3 .

Answer

3

Exercise #4

5b+300b=0 5b+300b=0

b=? b=\text{?}

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the like terms on the left-hand side of the equation.
  • Step 2: Combine like terms.
  • Step 3: Simplify the equation.
  • Step 4: Solve the equation for bb.

Now, let's work through each step:

Step 1: The given equation is 5b+300b=05b + 300b = 0.

Step 2: Combine like terms:

5b+300b=(5+300)b=305b5b + 300b = (5 + 300)b = 305b

So, the equation becomes 305b=0305b = 0.

Step 3: Since 305b=0305b = 0, we can solve for bb using the property of zero product:

If 305×b=0305 \times b = 0, then bb must be 00 because 3050305 \neq 0.

Therefore, the solution to the problem is b=0b = 0.

Answer

0 0

Exercise #5

3x+5=20 3x + 5 = 20

x=? x = \text{?}

Video Solution

Step-by-Step Solution

To solve the equation 3x+5=20 3x + 5 = 20 , follow these steps:

1. Subtract 5 from both sides: 3x=205 3x = 20 - 5

2. Simplify the right side: 3x=15 3x = 15

3. Divide both sides by 3: x=153 x = \frac{15}{3}

4. Solve: x=5 x = 5

Answer

5

Exercise #6

4x7=13 4x - 7 = 13

x=? x = \text{?}

Video Solution

Step-by-Step Solution

To solve the equation 4x7=13 4x - 7 = 13 , follow these steps:

1. Add 7 to both sides: 4x=13+7 4x = 13 + 7

2. Simplify the right side: 4x=20 4x = 20

3. Divide both sides by 4: x=204 x = \frac{20}{4}

4. Solve: x=5 x = 5

Answer

5

Exercise #7

4a+524+a=2a 4a+5-24+a=-2a

a=? a=?

Video Solution

Step-by-Step Solution

To solve the equation 4a+524+a=2a 4a + 5 - 24 + a = -2a , follow these steps:

  • Step 1: Start by combining like terms on the left side of the equation:

4a+a+524=2a 4a + a + 5 - 24 = -2a

This simplifies to:

5a19=2a 5a - 19 = -2a

  • Step 2: Move all terms involving a a to one side of the equation and constant terms to the other side:

Add 2a 2a to both sides to collect all terms with a a :

5a+2a=19 5a + 2a = 19

This simplifies to:

7a=19 7a = 19

  • Step 3: Solve for a a by dividing both sides by 7:

a=197 a = \frac{19}{7}

Thus, the value of a a is 197 \frac{19}{7} , which can be written as a mixed number:

a=257 a = 2\frac{5}{7} .

Upon verifying with the given choices, the correct answer is choice 1: 257 2\frac{5}{7} .

Answer

257 2\frac{5}{7}

Exercise #8

m+3m17m+6=20 m+3m-17m+6=-20

m=? m=\text{?}

Video Solution

Step-by-Step Solution

To solve the problem, we will use the following steps:

  • Step 1: Simplify the equation by combining like terms.
  • Step 2: Isolate the variable m m using algebraic methods.
  • Step 3: Solve for m m and verify the solution.

Let's begin:

Step 1: Simplify the equation m+3m17m+6=20 m + 3m - 17m + 6 = -20 .
Combine the coefficients of m m :

(1+317)m+6=20 (1 + 3 - 17)m + 6 = -20

This simplifies to:

13m+6=20 -13m + 6 = -20

Step 2: Isolate m m .
Subtract 6 from both sides:

13m+66=206 -13m + 6 - 6 = -20 - 6

Simplifies to:

13m=26 -13m = -26

Step 3: Solve for m m by dividing both sides by -13:

m=2613 m = \frac{-26}{-13}

The division simplifies to:

m=2 m = 2

Therefore, the solution to the problem is m=2 m = 2 , which corresponds to choice 2 in the given options.

Answer

2

Exercise #9

2+3a+4=0 2+3a+4=0

a=? a=\text{?}

Video Solution

Step-by-Step Solution

To solve the equation 2+3a+4=0 2 + 3a + 4 = 0 , follow these steps:

  • Step 1: Combine the constant terms on the left side.
    The terms 2 2 and 4 4 can be combined to get 6 6 .
    Hence, the equation becomes 3a+6=0 3a + 6 = 0 .
  • Step 2: Isolate the term with the variable a a .
    Subtract 6 6 from both sides to get 3a=6 3a = -6 .
  • Step 3: Solve for a a by dividing both sides by the coefficient of a a , which is 3 3 .
    Thus, a=63=2 a = \frac{-6}{3} = -2 .

Therefore, the solution to the problem is a=2 a = -2 .

Answer

2 -2

Exercise #10

132x=0 13-2x=0

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Subtract 13 from both sides of the equation to isolate the term with xx.
  • Step 2: Divide by 2-2 to solve for xx.

Now, let's work through each step:
Step 1: Begin by subtracting 13 from both sides:

132x13=01313 - 2x - 13 = 0 - 13
Which simplifies to:

2x=13-2x = -13

Step 2: Divide both sides by 2-2 to solve for xx:

2x2=132\frac{-2x}{-2} = \frac{-13}{-2}

This simplifies to:

x=132x = \frac{13}{2}

When expressed as a mixed number, xx equals:

x=612x = 6\frac{1}{2}.

Therefore, the solution to the problem is x=612x = 6\frac{1}{2}.

The correct answer choice is :

x=612x = 6\frac{1}{2}

.

Answer

x=612 x=6\frac{1}{2}

Exercise #11

20+20x3x=88 20+20x-3x=88

x=? x=\text{?}

Video Solution

Step-by-Step Solution

To solve this problem, we need to find x x in the equation:

20+20x3x=88 20 + 20x - 3x = 88

Step 1: Combine like terms on the left-hand side of the equation. The terms involving x x are 20x 20x and 3x-3x.

20x3x=17x 20x - 3x = 17x

Thus, the equation becomes:

20+17x=88 20 + 17x = 88

Step 2: Isolate the x x -related terms by moving the constant term to the right-hand side. To do this, subtract 20 from both sides:

17x=8820 17x = 88 - 20

17x=68 17x = 68

Step 3: Solve for x x by dividing both sides of the equation by 17:

x=6817 x = \frac{68}{17}

x=4 x = 4

Therefore, the solution to the problem is x=4 x = 4 .

Answer

4 4

Exercise #12

2y+125y+30=0 2y+12-5y+30=0

y=? y=\text{?}

Video Solution

Step-by-Step Solution

To solve the equation 2y+125y+30=0 2y + 12 - 5y + 30 = 0 , follow these steps:

  • Step 1: Simplify the equation by combining like terms.
    Combine the y y terms and the constant terms:
    2y5y+12+30=0 2y - 5y + 12 + 30 = 0
  • Step 2: Calculate the combined terms.
    2y5y=3y 2y - 5y = -3y
    12+30=42 12 + 30 = 42
    Thus, the equation becomes:
    3y+42=0 -3y + 42 = 0
  • Step 3: Isolate the variable y y .
    Subtract 42 from both sides to get:
    3y=42 -3y = -42
  • Step 4: Solve for y y by dividing both sides by 3-3:
    y=423 y = \frac{-42}{-3}
  • Step 5: Simplify the fraction:
    y=14 y = 14

Therefore, the solution to the equation is y=14 y = 14 .

Answer

14 14

Exercise #13

2b3b+4=5 2b-3b+4=5

b=? b=\text{?}

Video Solution

Step-by-Step Solution

Let's first arrange the equation so that on the left-hand side we have the terms with the coefficient b b and on the right-hand side the numbers without the coefficient b b .

Remember that when we move terms across the equals sign, the plus and minus signs will change accordingly:

2b3b=54 2b-3b=5-4

Let's now solve the subtraction exercise on both sides:

1b=1 -1b=1

Finally, we can divide both sides by -1 to find our answer:

b=1 b=-1

Answer

-1

Exercise #14

x4+2x18=0 \frac{x}{4}+2x-18=0

x=? x=\text{?}

Video Solution

Step-by-Step Solution

To solve the equation x4+2x18=0\frac{x}{4} + 2x - 18 = 0, we proceed as follows:

  • Step 1: Eliminate the fraction by multiplying the entire equation by 4:
    (4)(x4+2x18)=(4)(0)(4) \Big(\frac{x}{4} + 2x - 18\Big) = (4)(0)
  • Step 2: Distribute and simplify:
    x+8x72=0x + 8x - 72 = 0
  • Step 3: Combine like terms:
    9x72=09x - 72 = 0
  • Step 4: Isolate 9x9x by adding 72 to both sides:
    9x=729x = 72
  • Step 5: Solve for xx by dividing both sides by 9:
    x=729x = \frac{72}{9}
  • Step 6: Simplify the division:
    x=8x = 8

Thus, the solution to the problem is x=8x = 8.

Answer

8

Exercise #15

3x+4+8x15=0 3x+4+8x-15=0

x=? x=\text{?}

Video Solution

Step-by-Step Solution

To solve the equation 3x+4+8x15=0 3x + 4 + 8x - 15 = 0 , we begin by combining the terms that involve x x and the constant terms:

Step 1: Combine like terms.
The terms involving x x are 3x 3x and 8x 8x . Adding these yields:

11x 11x

The constant terms are +4 +4 and 15-15. Combining these gives:

+415=11 +4 - 15 = -11

Thus, the equation becomes:

11x11=0 11x - 11 = 0

Step 2: Solve for x x .
To isolate x x , add 11 to both sides of the equation:

11x11+11=0+11 11x - 11 + 11 = 0 + 11 11x=11 11x = 11

Now, divide both sides by 11:

x=1111 x = \frac{11}{11} x=1 x = 1

Therefore, the solution to the equation is x=1 x = 1 .

Answer

1 1

Exercise #16

12y+4y+53=2y 12y+4y+5-3=2y

y=? y=\text{?}

Video Solution

Step-by-Step Solution

To solve the equation 12y+4y+53=2y12y + 4y + 5 - 3 = 2y, we'll follow these steps:

  • **Step 1**: Simplify the left side of the equation by combining like terms: 12y+4y=16y12y + 4y = 16y.
  • **Step 2**: Replace that in the equation: 16y+53=2y16y + 5 - 3 = 2y. Simplify further to 16y+2=2y16y + 2 = 2y.
  • **Step 3**: Isolate yy by getting all the terms involving yy on one side. Subtract 2y2y from both sides, yielding: 16y2y=216y - 2y = -2.
  • **Step 4**: This simplifies to 14y=214y = -2.
  • **Step 5**: Divide each side by 14 to solve for yy: y=214y = \frac{-2}{14}.
  • **Step 6**: Simplify the fraction: y=17y = -\frac{1}{7}.

Therefore, the solution to the problem is y=17 y = -\frac{1}{7} .

Answer

17 -\frac{1}{7}

Exercise #17

2y1yy+4=8y 2y\cdot\frac{1}{y}-y+4=8y

y=? y=\text{?}

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Simplify the term 2y1y 2y \cdot \frac{1}{y}
  • Rearrange the equation to group similar terms
  • Solve for y y

Now, let's work through each step:

Step 1: Simplify the expression 2y1y 2y \cdot \frac{1}{y} .

The term 2y1y 2y \cdot \frac{1}{y} simplifies directly to 2 2 since y y in the numerator and denominator cancel each other out assuming y0 y \neq 0 . Therefore, the equation becomes:

2y+4=8y 2 - y + 4 = 8y

Step 2: Combine like terms on the left-hand side:

2+4=6 2 + 4 = 6 , so the equation now is 6y=8y 6 - y = 8y .

Step 3: Rearrange the equation to isolate y y on one side. Add y y to both sides to get rid of the negative y y :

6=8y+y 6 = 8y + y

This simplifies to:

6=9y 6 = 9y

Step 4: Solve for y y by dividing both sides by 9:

y=69 y = \frac{6}{9}

Simplify the fraction to get:

y=23 y = \frac{2}{3}

Therefore, the solution to the problem is 23 \frac{2}{3} .

Answer

23 \frac{2}{3}

Exercise #18

14y+12y+512=0 \frac{1}{4}y+\frac{1}{2}y+5-12=0

y=? y=\text{?}

Video Solution

Step-by-Step Solution

To solve the given linear equation, we will follow these steps:

  • Step 1: Combine the terms involving y y .
  • Step 2: Simplify the constants on the right side of the equation.
  • Step 3: Isolate y y to find its value.

Let’s solve the equation 14y+12y+512=0 \frac{1}{4}y + \frac{1}{2}y + 5 - 12 = 0 .

Step 1: Combine the like terms that involve y y .
The coefficients of y y are 14 \frac{1}{4} and 12 \frac{1}{2} . To combine them, we need a common denominator, which is 4. Therefore:

14y+12y=14y+24y=34y \frac{1}{4}y + \frac{1}{2}y = \frac{1}{4}y + \frac{2}{4}y = \frac{3}{4}y .

Step 2: Simplify the constants.
The equation now becomes 34y+512=0 \frac{3}{4}y + 5 - 12 = 0 .
Combine the constants: 512=7 5 - 12 = -7 .

The equation simplifies to 34y7=0 \frac{3}{4}y - 7 = 0 .

Step 3: Isolate y y .
Add 7 to both sides of the equation:
34y=7 \frac{3}{4}y = 7 .

To solve for y y , multiply both sides by the reciprocal of 34 \frac{3}{4} , which is 43 \frac{4}{3} :

y=7×43=283 y = 7 \times \frac{4}{3} = \frac{28}{3} .

Convert the fraction to a mixed number: 283=93+1=9 remainder 1 \frac{28}{3} = 9 \cdot 3 + 1 = 9 \text{ remainder } 1. Thus, 283=913 \frac{28}{3} = 9\frac{1}{3} .

Therefore, the value of y y is 913 9\frac{1}{3} .

Answer

913 9\frac{1}{3}

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