3x−x=8
x=?
\( 3x - x = 8 \)
\( x = \text{?} \)
\( 4x + 2x = 18 \)
Solve the equation above for \( x \).
\( 2b-3b+4=5 \)
\( b=\text{?} \)
\( 3x + 5 = 20 \)
\( x = \text{?} \)
\( 4x - 7 = 13 \)
\( x = \text{?} \)
Start by simplifying the left-hand side of the equation:
So the equation becomes:
To find the value of , divide both sides by 2:
Then simplify the fraction:
Thus, the solution to the equation is.
4
Solve the equation above for .
Combine like terms on the left-hand side:
The equation becomes:
Divide both sides by 6 to solve for :
Simplify the division:
Thus, is the solution to the equation.
Let's arrange the equation so that on the left side we have the terms with coefficient b and on the right side the numbers without coefficient b
We'll remember that when we move terms across the equals sign, the plus and minus signs will change accordingly:
Let's solve the subtraction exercise on both sides:
Let's divide both sides by minus 1:
-1
To solve the equation , follow these steps:
1. Subtract 5 from both sides:
2. Simplify the right side:
3. Divide both sides by 3:
4. Solve:
5
To solve the equation , follow these steps:
1. Add 7 to both sides:
2. Simplify the right side:
3. Divide both sides by 4:
4. Solve:
5
\( 5b+300b=0 \)
\( b=\text{?} \)\( \)
\( x+2x=9 \)
\( x=\text{?} \)
\( 13-2x=0 \)
\( 20+20x-3x=88 \)
\( x=\text{?} \)
\( 2+3a+4=0 \)
\( a=\text{?} \)
3
\( 2y+12-5y+30=0 \)
\( y=\text{?} \)
\( 4a+5-24+a=-2a \)
\( a=? \)
\( \frac{x}{4}+2x-18=0 \)
\( x=\text{?} \)\( \)
\( m+3m-17m+6=-20 \)
\( m=\text{?} \)
\( 12y+4y+5-3=2y \)
\( y=\text{?} \)
8
2
\( 2y\cdot\frac{1}{y}-y+4=8y \)
\( y=\text{?} \)
\( 3x+4+8x-15=0 \)
\( x=\text{?} \)
\( \frac{1}{4}y+\frac{1}{2}y+5-12=0 \)
\( y=\text{?} \)