2b−3b+4=5
b=?
\( 2b-3b+4=5 \)
\( b=\text{?} \)
\( 5b+300b=0 \)
\( b=\text{?} \)\( \)
\( x+2x=9 \)
\( x=\text{?} \)
\( 13-2x=0 \)
\( 20+20x-3x=88 \)
\( x=\text{?} \)
Let's arrange the equation so that on the left side we have the terms with coefficient b and on the right side the numbers without coefficient b
We'll remember that when we move terms across the equals sign, the plus and minus signs will change accordingly:
Let's solve the subtraction exercise on both sides:
Let's divide both sides by minus 1:
-1
3
\( 2+3a+4=0 \)
\( a=\text{?} \)
\( 2y+12-5y+30=0 \)
\( y=\text{?} \)
\( \frac{x}{4}+2x-18=0 \)
\( x=\text{?} \)\( \)
\( \frac{1}{4}y+\frac{1}{2}y+5-12=0 \)
\( y=\text{?} \)
8