Applying Combined Exponents Rules: Single Variable

We use the formula:

$(a^m)^n=a^{m\times n}$

and therefore we obtain:

$(a^5)^7=a^{5\times7}=a^{35}$

To solve this problem, we need to simplify the expression $\frac{b^5}{b^2}$ using the rules of exponents.

• Step 1: Identify the rule to apply: For any positive integer exponents $m$ and $n$, the rule $\frac{a^m}{a^n} = a^{m-n}$ applies when dividing terms with the same base. In this expression, our base is $b$.

• Step 2: Apply the rule: Substitute the given exponents into the formula: $\frac{b^5}{b^2} = b^{5-2}$

• Step 3: Perform the subtraction: Calculate the exponent $5 - 2$: $b^{5-2} = b^3$

Therefore, the solution to the expression $\frac{b^5}{b^2}$ is $b^3$.

To solve the given expression $\frac{x^6}{x^4}$, we will follow these steps:

• Step 1: Apply the quotient rule for exponents
• Step 2: Simplify the expression
• Step 3: Verify by comparing with the answer choices

Now, let's work through each step:

Step 1: Apply the quotient rule for exponents. This rule states that $\frac{a^m}{a^n} = a^{m-n}$ when dividing powers with the same base.

Step 2: We have $\frac{x^6}{x^4}$. According to the rule:

$\frac{x^6}{x^4} = x^{6-4} = x^2$

Step 3: Verify by comparing with the answer choices:

• Choice 1: $x^{-2}$ – Incorrect as it implies the exponents were added incorrectly.
• Choice 2: $x^2$ – This matches our result.
• Choice 3: $x^{10}$ – Incorrect as it implies the exponents were added instead of subtracted.
• Choice 4: $x^{\frac{2}{3}}$ – Incorrect as it does not match the calculation based on integer exponents.

Therefore, the correct choice is $x^2$, which is Choice 2.

To simplify the expression $(x^3)^4$, we'll follow these steps:

• Step 1: Identify the expression: $(x^3)^4$.
• Step 2: Apply the formula for a power raised to another power.
• Step 3: Calculate the product of the exponents.

Now, let's work through each step:

Step 1: We have the expression $(x^3)^4$, which involves a power raised to another power.

Step 2: We apply the exponent rule $(a^m)^n = a^{m \cdot n}$ here with $a = x$, $m = 3$, and $n = 4$.

Step 3: Multiply the exponents: $3 \times 4 = 12$. This gives us a new exponent for the base $x$.

Therefore, $(x^3)^4 = x^{12}$.

Consequently, the correct answer choice is: $x^{12}$ from the options provided. The other options $x^6$, $x^1$, and $x^7$ do not reflect the correct application of the exponent multiplication rule.

To solve the expression $\frac{y^9}{y^3}$, we will apply the rules of exponents, specifically the power of division rule, which states that when you divide like bases, you subtract the exponents.

Here are the steps to arrive at the solution:

• Step 1: Identify and write down the expression: $\frac{y^9}{y^3}$.

• Step 2: Apply the division rule of exponents, which is $\frac{a^m}{a^n} = a^{m-n}$, for any non-zero base $a$.

• Step 3: Using the division rule, subtract the exponent in the denominator from the exponent in the numerator:$y^{9-3}$

• Step 4: Calculate the exponent: $9 - 3 = 6$

• Step 5: Write down the simplified expression:$y^6$

Therefore, the expression $\frac{y^9}{y^3}$ simplifies to $y^6$.

To reduce the expression $a^2 \times a^5 \times a^3$, we will apply the product of powers property of exponents. This property states that when multiplying expressions with the same base, we add their exponents.

• Step 1: Identify the exponents.
  The expression involves the same base $a$ with exponents: 2, 5, and 3.
• Step 2: Add the exponents.
  According to the product of powers property, $a^2 \times a^5 \times a^3 = a^{2+5+3}$.
• Step 3: Simplify the expression.
  Calculate the sum of the exponents: $2 + 5 + 3 = 10$. Therefore, the expression simplifies to $a^{10}$.

Ultimately, the solution to the problem is $a^{10}$. Among the provided choices, is correct: $a^{10}$. The other options $a^5$, $a^8$, and $a^4$ do not correctly reflect the sum of the exponents as calculated.

First we rewrite the first expression on the left of the problem as a fraction:

$\frac{a^2}{a}+a^3\cdot a^5$Then we use two properties of exponentiation, to multiply and divide terms with identical bases:

1.

$b^m\cdot b^n=b^{m+n}$

2.

$\frac{b^m}{b^n}=b^{m-n}$

Returning to the problem and applying the two properties of exponentiation mentioned earlier:

$\frac{a^2}{a}+a^3\cdot a^5=a^{2-1}+a^{3+5}=a^1+a^8=a+a^8$

Later on, keep in mind that we need to factor the expression we obtained in the last step by extracting the common factor,

Therefore, we extract from outside the parentheses the greatest common divisor to the two terms which are:

$a$ We obtain the expression:

$a+a^8=a(1+a^7)$ when we use the property of exponentiation mentioned earlier in A.

$$$a^8=a^{1+7}=a^1\cdot a^7=a\cdot a^7$

Summarizing the solution to the problem and all the steps, we obtained the following:

$\frac{a^2}{a}+a^3\cdot a^5=a(1+a^{7)}$

Therefore, the correct answer is option b.

We'll begin by applying the multiplication law between fractions, multiplying numerator by numerator and denominator by denominator:

$\frac{x}{y}\cdot\frac{w}{z}=\frac{x\cdot w}{y\cdot z}$

Let's return to the problem and apply the above law:

$\frac{a^{12}}{a^9}\cdot\frac{a^3}{a^4}=\frac{a^{12}\cdot a^3}{a^{^9}\cdot a^4}$

From here on we will no longer indicate the multiplication sign, instead we will place the terms next to each other.

Note that in both the numerator and denominator, multiplication is performed between terms with identical bases, therefore we'll apply the power law for multiplication between terms with the same base:

$b^m\cdot b^n=b^{m+n}$

Note that this law can only be used to calculate multiplication between terms with identical bases.

Let's return to the problem and calculate separately the results of the multiplication in the numerator and denominator:

$\frac{a^{12}a^3}{a^{^9}a^4}=\frac{a^{12+3}}{a^{9+4}}=\frac{a^{15}}{a^{13}}$

In the last step we calculated the sum of the exponents.

Now we need to perform division (fraction=division operation between numerator and denominator) between terms with identical bases, therefore we'll apply the power law for division between terms with the same base:

$\frac{b^m}{b^n}=b^{m-n}$

Note that this law can only be used to calculate division between terms with identical bases.

Let's return to the problem and apply the above law:

$\frac{a^{15}}{a^{13}}=a^{15-13}=a^2$

In the last step we calculated the result of the subtraction operation in the exponent.

We cannot simplify the expression further. Therefore the correct answer is D.

To solve this problem, we need to simplify the given expression using the rules of exponents:

First, simplify inside the brackets:
$\frac{a^4}{a^3} \times \frac{a^8}{a^7} = a^{4-3} \times a^{8-7} = a^1 \times a^1 = a^{1+1} = a^2$

Now, handle the entire expression, dividing it by $\frac{a^{10}}{a^8}$:
$\frac{a^2}{\frac{a^{10}}{a^8}} = a^2 \times \frac{a^8}{a^{10}} = a^2 \times a^{8-10} = a^2 \times a^{-2} = a^{2 + (-2)} = a^0$

Recall that any non-zero number raised to the power of zero is 1, hence: $a^0 = 1$

Therefore, the solution to the problem is $1$.

Let's start with multiplying the fractions, remembering that the multiplication of fractions is performed by multiplying the numerator by numerator and the denominator by the denominator:

$\frac{b^{22}}{b^{20}}\cdot\frac{b^{30}}{b^{20}}=\frac{b^{22}\cdot b^{30}}{b^{20}\cdot b^{20}}$

In both the numerator and denominator, multiplication occurs between terms with identical bases, so we'll apply the power law for multiplying terms with identical bases:

$c^m\cdot c^n=c^{m+n}$

This law can only be used when multiplication is performed between terms with identical bases.

From here on, we will no longer indicate the multiplication sign, instead we will place terms next to each other.
Let's return to the problem and apply the above power law separately to the fraction's numerator and denominator:

$\frac{b^{22}b^{30}}{b^{20}b^{20}}=\frac{b^{22+30}}{b^{20+20}}=\frac{b^{52}}{b^{40}}$

In the final step we calculated the sum of the exponents in the numerator and denominator.

Note that division is required between two terms with identical bases, hence we'll apply the power law for division between terms with identical bases:

$\frac{c^m}{c^n}=c^{m-n}$

This law can only be used when division is performed between terms with identical bases.

Let's return to the problem and apply the above power law:

$\frac{b^{52}}{b^{40}}=b^{52-40}=b^{12}$

In the final step we calculated the subtraction between the exponents.

This is the most simplified form of the expression:

Therefore, the correct answer is C.

We use the power law for multiplication within parentheses:

$(x\cdot y)^n=x^n\cdot y^n$

We apply it in the problem:

$(y\cdot7\cdot3)^4=y^4\cdot7^4\cdot3^4$

Therefore, the correct answer is option a.

Note:

From the formula of the power property mentioned above, we can understand that it applies not only to two terms within parentheses, but also for multiple terms within parentheses.

We use the formula:

$(a^m)^n=a^{m\times n}$

$(4^2)^3+(g^3)^4=4^{2\times3}+g^{3\times4}=4^6+g^{12}$

We use the power rule of distributing exponents.

$(a^m)^n=a^{m\cdot n}$We apply it in the problem:

$\big((y^6)^8\big)^9=(y^{6\cdot8})^9=y^{6\cdot8\cdot9}=y^{432}$When we use the aforementioned rule twice, the first time for the inner parentheses in the first stage and the second time for the remaining parentheses in the second stage, in the last stage we calculate the result of the multiplication in the power exponent.

Therefore, the correct answer is option b.

We use the formula

$(a^m)^n=a^{m\times n}$

Therefore, we obtain:

$a^{4\times6}=a^{24}$

We use the formula

$(a^m)^n=a^{m\times n}$

Therefore, we obtain:

$((b^3)^6)^2=(b^{3\times6})^2=(b^{18})^2=b^{18\times2}=b^{36}$

We use the formula:

$(a\times b)^n=a^nb^n$

$(5\times x\times3)^3=(15x)^3$

$(15x)^3=(15\times x)^3$

$15^3x^3$

Let us begin by using the law of exponents for a power that is applied to parentheses in which terms are multiplied:

$(x\cdot y)^n=x^n\cdot y^n$

We apply the rule to our problem:

$(x\cdot4\cdot3)^3= x^3\cdot4^3\cdot3^3$

When we apply the power to the product of the terms within parentheses, we apply the power to each term of the product separately and keep the product,

Therefore, the correct answer is option C.

We use the power property to multiply terms with identical bases:

$a^m\cdot a^n=a^{m+n}$We apply it in the problem:

$Y^2+Y^6-Y^5\cdot Y=Y^2+Y^6-Y^{5+1}=Y^2+Y^6-Y^6=Y^2$When we apply the previous property to the third expression from the left in the sum, and then simplify the total expression by adding like terms.

Therefore, the correct answer is option D.

We begin by using the negative exponent rule.

$b^{-n}=\frac{1}{b^n}$We apply it to the problem:

$$$$$a^{-4}=\frac{1}{a^4}$Therefore, the correct answer is option B.

We use the power rule for exponents.

$(a^m)^n=a^{m\cdot n}$We apply it to the problem:

$\big((a^2)^3\big)^{\frac{1}{4}}=(a^{2\cdot3})^{\frac{1}{4}}=a^{2\cdot3\cdot\frac{1}{4}}=a^{\frac{6}{4}}=a^{\frac{3}{2}}$When we use the previously mentioned rule twice, the first time for the inner parentheses in the first stage and the second time for the remaining parentheses in the second stage, in the third stage we calculate the result of the multiplication in the exponent. While remembering that multiplying by a fraction is actually doubling the numerator of the fraction and, finally, in the last stage we simplify the fraction we obtained in the exponent.

Now remember that -

$\frac{3}{2}=1\frac{1}{2}=1.5$

Therefore, the correct answer is option a.