Solving Radical Expression: Simplify ⁶√b¹²×(1/b)²×a

Question

b126(1b)2a=? \sqrt[6]{b^{12}}\cdot(\frac{1}{b})^2\cdot a=\text{?}

Video Solution

Solution Steps

00:11 Let's simplify this problem step-by-step.
00:16 Find the Nth root of a number raised to the power of M.
00:20 This equals the number to the power of M divided by N.
00:24 Now we will apply this formula to our problem.
00:38 Remember, with a fraction in the exponent, raise both the top and bottom to that power.
00:47 Let's use this formula in our exercise now.
00:51 Simplify wherever you can!
00:59 And that's our solution. Great job!

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Simplify b126 \sqrt[6]{b^{12}} using fractional exponent form.
  • Step 2: Simplify the expression (1b)2 \left(\frac{1}{b}\right)^2 using negative exponents.
  • Step 3: Combine and simplify the entire expression.

Now, let's work through each step:

Step 1: Simplify b126 \sqrt[6]{b^{12}} .
The expression b126 \sqrt[6]{b^{12}} can be rewritten using fractional exponents as b12/6=b2 b^{12/6} = b^2 .

Step 2: Simplify (1b)2 \left(\frac{1}{b}\right)^2 .
The expression (1b)2 \left(\frac{1}{b}\right)^2 simplifies using negative exponents: b2 b^{-2} .

Step 3: Combine the simplified expressions and the original variable a a .
Combine all components as follows:
b2b2a b^2 \cdot b^{-2} \cdot a .
Using the property xmxn=xm+n x^m \cdot x^n = x^{m+n} , we have:
b2+(2)a=b0a b^{2 + (-2)} \cdot a = b^0 \cdot a .
Since b0=1 b^0 = 1 (by the zero exponent rule), the expression simplifies to:
a a .

Therefore, the solution to the problem is a a .

Answer

a a