Solving Radical Expression: Simplify ⁶√b¹²×(1/b)²×a

Question

b126(1b)2a=? \sqrt[6]{b^{12}}\cdot(\frac{1}{b})^2\cdot a=\text{?}

Video Solution

Solution Steps

00:00 Simplify the following problem
00:03 The Nth root of a number raised to the power of M
00:07 Is equal to the number raised to the power of M divided by N
00:10 We will apply this formula to our exercise
00:27 When there's a fraction in the exponent, both the numerator and the denominator will be raised to the power
00:36 Apply this formula to our exercise
00:40 Simplify wherever possible
00:48 This is the solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Simplify b126 \sqrt[6]{b^{12}} using fractional exponent form.
  • Step 2: Simplify the expression (1b)2 \left(\frac{1}{b}\right)^2 using negative exponents.
  • Step 3: Combine and simplify the entire expression.

Now, let's work through each step:

Step 1: Simplify b126 \sqrt[6]{b^{12}} .
The expression b126 \sqrt[6]{b^{12}} can be rewritten using fractional exponents as b12/6=b2 b^{12/6} = b^2 .

Step 2: Simplify (1b)2 \left(\frac{1}{b}\right)^2 .
The expression (1b)2 \left(\frac{1}{b}\right)^2 simplifies using negative exponents: b2 b^{-2} .

Step 3: Combine the simplified expressions and the original variable a a .
Combine all components as follows:
b2b2a b^2 \cdot b^{-2} \cdot a .
Using the property xmxn=xm+n x^m \cdot x^n = x^{m+n} , we have:
b2+(2)a=b0a b^{2 + (-2)} \cdot a = b^0 \cdot a .
Since b0=1 b^0 = 1 (by the zero exponent rule), the expression simplifies to:
a a .

Therefore, the solution to the problem is a a .

Answer

a a