(23)6= (2^3)^6 = (23)6=
To solve the given expression (23)6 (2^3)^6 (23)6, we apply the power of a power rule (am)n=am⋅n (a^m)^n = a^{m \cdot n} (am)n=am⋅n. Here, a=2 a = 2 a=2, m=3 m = 3 m=3, and n=6 n = 6 n=6.
Thus, we calculate the exponent:
3⋅6=18 3 \cdot 6 = 18 3⋅6=18
So, (23)6=218 (2^3)^6 = 2^{18} (23)6=218.
218 2^{18} 218