809⋅3=?
\( \frac{9\cdot3}{8^0}=\text{?} \)
\( 7^4\cdot8^3\cdot(\frac{1}{7})^4=\text{?} \)
\( 5^{-3}\cdot5^0\cdot5^2\cdot5^5= \)
\( \frac{4^0\cdot6^7}{36^4\cdot9^0}=\text{?} \)
\( 4^5-4^6\cdot\frac{1}{4}=\text{?} \)
We use the formula:
We know that:
Therefore, we obtain:
We use the formula:
We use the formula:
We decompose the fraction inside of the parentheses:
We obtain:
We simplify the powers:
We obtain:
Remember that the number 1 in any power is equal to 1, thus we obtain:
We use the power property to multiply terms with identical bases:
Keep in mind that this property is also valid for several terms in the multiplication and not just for two, for example for the multiplication of three terms with the same base we obtain:
When we use the mentioned power property twice, we could also perform the same calculation for four terms of the multiplication of five, etc.,
Let's return to the problem:
Keep in mind that all the terms of the multiplication have the same base, so we will use the previous property:
Therefore, the correct answer is option c.
Note:
Keep in mind that
0
\( 5^3+5^{-3}\cdot5^3=\text{?} \)
\( \frac{(-3)^5\cdot8^4}{(-3)^3(-3)^2(-3)^{-5}}=\text{?} \)
\( \frac{2^0\cdot3^{-4}}{5^4\cdot9^2}=\text{?} \)
\( \frac{9^2\cdot3^{-4}}{6^3}=\text{?} \)
\( 3^{-3}\cdot\frac{19^{35}\cdot19^{-32}}{19^3}=\text{?} \)
\( \sqrt[6]{b^{12}}\cdot(\frac{1}{b})^2\cdot a=\text{?} \)