Solve the Fractional Equation: What Equals X in 70x + 4/3 + 6/9 = 68x - 15x?

To solve the equation $70x + \frac{4}{3} + \frac{6}{9} = 68x - 15x$, let's proceed with the following steps:

First, simplify the fractions on the left side. Notice that $\frac{6}{9}$ simplifies to $\frac{2}{3}$.

So the equation becomes:

$70x + \frac{4}{3} + \frac{2}{3} = 68x - 15x$

Next, combine the fractions on the left side:

$70x + \left(\frac{4}{3} + \frac{2}{3}\right) = 68x - 15x$

This results in:

$70x + \frac{6}{3} = 68x - 15x$

The fraction $\frac{6}{3}$ simplifies to 2, resulting in:

$70x + 2 = 68x - 15x$

Now, simplify the right side by combining like terms:

$70x + 2 = 53x$

Subtract $53x$ from both sides to isolate terms involving $x$ on one side:

$70x - 53x + 2 = 0$

This simplifies to:

$17x + 2 = 0$

Subtract 2 from both sides to isolate the term with $x$:

$17x = -2$

Finally, divide both sides by 17 to solve for $x$:

$x = -\frac{2}{17}$

Therefore, the solution to the problem is $x = -\frac{2}{17}$.