Solve the Complex Fraction: (13/126)^(x+y) Expression Completion

Insert the corresponding expression:

(137×6×3)x+y= \left(\frac{13}{7\times6\times3}\right)^{x+y}=

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1

Understand the problem

Insert the corresponding expression:

(137×6×3)x+y= \left(\frac{13}{7\times6\times3}\right)^{x+y}=

2

Step-by-step solution

Let's start by examining the expression given in the question:

(137×6×3)x+y \left(\frac{13}{7\times6\times3}\right)^{x+y}

This expression is a power of a fraction. There is a general rule in exponents which states:

(ab)n=anbn \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n}

Using this rule, we will apply it to our original expression.

Given, a=13 a = 13 , b=7×6×3 b = 7\times6\times3 , and n=x+y n = x+y , we can rewrite our expression as:

13x+y(7×6×3)x+y \frac{13^{x+y}}{(7\times6\times3)^{x+y}}

The solution to the question is:

13x+y(7×6×3)x+y \frac{13^{x+y}}{(7\times6\times3)^{x+y}}

3

Final Answer

13x+y(7×6×3)x+y \frac{13^{x+y}}{\left(7\times6\times3\right)^{x+y}}

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\( 112^0=\text{?} \)

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