Solve (2×4×5)/7 Raised to Power a: Complete the Expression

Question

Insert the corresponding expression:

(2×4×57)a= \left(\frac{2\times4\times5}{7}\right)^a=

Video Solution

Solution Steps

00:00 Simplify the following problem
00:04 According to the laws of exponents, a fraction raised to the power (N)
00:07 equals the numerator and denominator raised to the same power (N)
00:12 We will apply this formula to our exercise
00:21 According to the laws of exponents when a product is raised to the power (N)
00:24 it is equal to each factor in the product separately raised to the same power (N)
00:30 We will apply this formula to our exercise
00:41 This is the solution

Step-by-Step Solution

To solve this problem, we'll apply the exponent rule for fractions and products.

  • The given expression is (2×4×57)a \left(\frac{2 \times 4 \times 5}{7}\right)^a . We need to simplify this using exponent rules.
  • First, apply the exponent to both the numerator 2×4×52 \times 4 \times 5 and the denominator 77:
    (2×4×57)a=(2×4×5)a7a \left(\frac{2 \times 4 \times 5}{7}\right)^a = \frac{(2 \times 4 \times 5)^a}{7^a} .
  • Now, apply the rule (ab)n=an×bn (ab)^n = a^n \times b^n to distribute the exponent on the numerator:
  • (2×4×5)a=2a×4a×5a(2 \times 4 \times 5)^a = 2^a \times 4^a \times 5^a.
  • Therefore, the expression simplifies to:
    2a×4a×5a7a \frac{2^a \times 4^a \times 5^a}{7^a} .

Therefore, the expression simplifies to 2a×4a×5a7a \frac{2^a \times 4^a \times 5^a}{7^a} .

Answer

2a×4a×5a7a \frac{2^a\times4^a\times5^a}{7^a}