Solve for x in (3/10)^x: Complete the Exponential Expression

Exponent Distribution with Fractional Bases

Insert the corresponding expression:

(32×5)x= \left(\frac{3}{2\times5}\right)^x=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:10 Let's simplify this problem together.
00:14 Remember, if you have a fraction with a power N, both the top and bottom get the same power N.
00:20 So each part of the fraction will be raised to the power of N.
00:25 Now let's try this out with our example.
00:28 When you have a product with a power N, it means each factor gets that power.
00:34 Let’s apply this law to see what happens.
00:38 We'll use this rule in our calculation now.
00:43 And that gives us our solution.

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Insert the corresponding expression:

(32×5)x= \left(\frac{3}{2\times5}\right)^x=

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the given expression.
  • Step 2: Apply the exponent rule (ab)n=anbn\left(\frac{a}{b}\right)^n = \frac{a^n}{b^n} to distribute xx to numerator and denominator.
  • Step 3: Simplify the denominator expression by distributing exponent xx to each factor.

Now, let's work through each step:
Step 1: We have the original expression (32×5)x\left(\frac{3}{2 \times 5}\right)^x.
Step 2: Apply the rule to get 3x(2×5)x\frac{3^x}{(2 \times 5)^x}.
Step 3: Expand the denominator: (2×5)x=2x×5x(2 \times 5)^x = 2^x \times 5^x. This leads us to 3x2x×5x\frac{3^x}{2^x \times 5^x}.

Therefore, the solution to the problem is 3x2x×5x \frac{3^x}{2^x \times 5^x} .

3

Final Answer

3x2x×5x \frac{3^x}{2^x\times5^x}

Key Points to Remember

Essential concepts to master this topic
  • Rule: Apply (ab)n=anbn \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n} to distribute exponents
  • Technique: Expand (2×5)x (2 \times 5)^x to 2x×5x 2^x \times 5^x
  • Check: Verify by substituting a test value like x=2 into both forms ✓

Common Mistakes

Avoid these frequent errors
  • Leaving the denominator as (2×5)^x without expanding
    Don't write 3x(2×5)x \frac{3^x}{(2 \times 5)^x} as your final answer! This doesn't fully apply the exponent distribution rule and misses a crucial simplification step. Always expand (2×5)x (2 \times 5)^x to 2x×5x 2^x \times 5^x using the product power rule.

Practice Quiz

Test your knowledge with interactive questions

\( 112^0=\text{?} \)

FAQ

Everything you need to know about this question

Why can't I just leave it as (2×5)^x in the denominator?

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While (2×5)x (2 \times 5)^x is mathematically correct, the question asks for the complete expression. You need to apply the product power rule: (ab)n=an×bn (ab)^n = a^n \times b^n to get 2x×5x 2^x \times 5^x .

What's the difference between (2×5)^x and 2^x×5^x?

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They're mathematically equal but represent different stages of simplification! (2×5)x=2x×5x (2 \times 5)^x = 2^x \times 5^x because of the product power rule. The expanded form shows each base raised to the power separately.

How do I remember the fraction exponent rule?

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Think of it as "exponent goes to both floors" - the numerator and denominator each get the exponent! So (ab)n \left(\frac{a}{b}\right)^n becomes anbn \frac{a^n}{b^n} .

Can I simplify 2×5 to 10 first?

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You could, but that would give you 3x10x \frac{3^x}{10^x} , which is different from the required answer 3x2x×5x \frac{3^x}{2^x \times 5^x} . The question wants you to keep the factors separate.

What if I get confused about which rule to apply when?

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Start with the quotient power rule first: (ab)n=anbn \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n} . Then, if the denominator has multiplication, apply the product power rule: (ab)n=anbn (ab)^n = a^n b^n .

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