Solve Linear Equation: -33x+45-58 = 38x+144-15

Question

Find the value of the parameter X

33x+4558=38x+14415 -33x+45-58=38x+144-15

Video Solution

Solution Steps

00:00 Find X
00:04 Collect terms
00:17 Arrange the equation so that one side has only the unknown X
00:38 Isolate X
00:49 This is the solution to the question

Step-by-Step Solution

To solve the equation 33x+4558=38x+14415 -33x + 45 - 58 = 38x + 144 - 15 , we will simplify both sides:

  • First, combine like terms on the left side: 4558=13 45 - 58 = -13 .
  • This gives us: 33x13=38x+14415 -33x - 13 = 38x + 144 - 15 .
  • Now, simplify the right side: 14415=129 144 - 15 = 129 .
  • The equation now is: 33x13=38x+129 -33x - 13 = 38x + 129 .

Next, we'll move all x x -terms to one side:

  • Add 33x 33x to both sides: 33x+33x13=38x+33x+129 -33x + 33x - 13 = 38x + 33x + 129 .
  • This simplifies to: 13=71x+129 -13 = 71x + 129 .

Now, isolate the x x -term:

  • Subtract 129 from both sides: 13129=71x -13 - 129 = 71x .
  • This results in: 142=71x -142 = 71x .

Finally, solve for x x by dividing both sides by 71:

  • x=14271 x = -\frac{142}{71} .
  • Simplifying this fraction: x=2 x = -2 .

The correct value of x x is x=2 x = -2 . This corresponds to choice 3.

Answer

2 -2