Solve (5/9)^(2x+1): Complete the Exponential Expression

Question

Insert the corresponding expression:

(59)2x+1= \left(\frac{5}{9}\right)^{2x+1}=

Video Solution

Solution Steps

00:00 Simplify the following problem
00:04 According to the laws of exponents, a fraction raised to the power (N)
00:07 equals the numerator and denominator raised to the same power (N)
00:11 Note that each exponent (N) contains an addition operation
00:14 We will apply this formula to our exercise
00:17 This is the solution

Step-by-Step Solution

To solve this problem, we'll apply the power of a fraction rule, which states that (ab)n=anbn\left(\frac{a}{b}\right)^n = \frac{a^n}{b^n}.

Step 1: Recognize the given expression: (59)2x+1\left(\frac{5}{9}\right)^{2x+1}.

Step 2: Apply the exponent rule to rewrite the expression. According to the rule, this becomes:

(59)2x+1=52x+192x+1\left(\frac{5}{9}\right)^{2x+1} = \frac{5^{2x+1}}{9^{2x+1}}.

Therefore, the expression can be rewritten as 52x+192x+1\frac{5^{2x+1}}{9^{2x+1}}.

Among the given choices, the correct option is choice 1: 52x+192x+1\frac{5^{2x+1}}{9^{2x+1}}.

Thus, the solution to the problem is 52x+192x+1 \frac{5^{2x+1}}{9^{2x+1}} .

Answer

52x+192x+1 \frac{5^{2x+1}}{9^{2x+1}}