Solve for X: 3x + 2/3 = 4(x + 1/12) Linear Equation

Question

3x+23=4(x+112) 3x+\frac{2}{3}=4(x+\frac{1}{12})

x=? x=\text{?}

Video Solution

Solution Steps

00:00 Solve
00:04 Open brackets properly, multiply by each factor
00:10 We want to isolate the unknown X
00:16 Let's arrange the equation so that X is only on one side
00:47 Let's break down 12 into factors 4 and 3
00:52 Let's reduce what we can
01:04 Convert from negative to positive
01:10 And this is the solution to the question

Step-by-Step Solution

To solve the equation 3x+23=4(x+112)3x + \frac{2}{3} = 4 \left(x + \frac{1}{12}\right), we follow these steps:

Step 1: Distribute the 4 on the right-hand side.

4(x+112)=4x+4124(x + \frac{1}{12}) = 4x + \frac{4}{12} which simplifies to 4x+134x + \frac{1}{3}.

Step 2: Write down the modified equation.

The equation now reads: 3x+23=4x+133x + \frac{2}{3} = 4x + \frac{1}{3}.

Step 3: Rearrange the equation to collect like terms.

Subtract 3x3x from both sides: 3x+233x=4x+133x3x + \frac{2}{3} - 3x = 4x + \frac{1}{3} - 3x.

This simplifies to: 23=x+13\frac{2}{3} = x + \frac{1}{3}.

Step 4: Isolate xx.

Subtract 13\frac{1}{3} from both sides: 2313=x\frac{2}{3} - \frac{1}{3} = x.

This simplifies to: x=13x = \frac{1}{3}.

Therefore, the solution to the equation is 13\boxed{\frac{1}{3}}.

Answer

13 \frac{1}{3}