In eighth grade there are a total of 28 students.
If there are 3 times as many boys as girls in the class.
Determine how many boys there are in total:
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In eighth grade there are a total of 28 students.
If there are 3 times as many boys as girls in the class.
Determine how many boys there are in total:
To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: Let be the number of girls. According to the problem, there are 3 times as many boys as girls, so the number of boys is .
Step 2: Since the total number of students is 28, we set up the equation:
Step 3: Combine like terms to simplify the equation:
To solve for , divide both sides by 4:
Step 4: Calculate the number of boys as :
Therefore, the solution to the problem is 21 boys in the class.
21
Solve for X:
\( x - 3 + 5 = 8 - 2 \)
Because that ignores the girls! The ratio is between boys and girls, not boys and total students. You need to account for both groups adding up to 28.
Choose the smaller group as your main variable. Since there are 3 times as many boys as girls, girls are fewer, so let g = girls.
Then you'd let b = boys and girls = 3b. The setup changes based on which group is described as 'times as many' as the other.
Divide the larger number by the smaller: . This confirms there are exactly 3 times as many boys as girls.
Check your work! You cannot have fractional people in a real classroom. A decimal answer usually means there's an error in your setup or calculation.
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