Solve (-4)+2+(-3)+(-5): Adding Multiple Negative Numbers

$(-4)+2+(-3)+(-5)=$

Let's start with the leftmost exercise:

$(-4)+2$

We'll locate negative 4 on the axis and move two steps to the right, where each step represents one whole number:

We can see that we've reached negative 2.

Now we'll get the exercise:

$(-2)+(-3)+(-5)=$

Let's focus on the exercise:

$(-2)+(-3)$

We'll locate negative 2 on the axis and move three steps to the left, where each step represents one whole number:

We can see that we've reached negative 5.

Now we'll get the exercise:

$(-5)+(-5)=$

We'll locate negative 5 on the axis and move five steps to the left, where each step represents one whole number:

We can see that we've reached negative 10.