Solve (35+4)×(10+5): Order of Operations Practice

(35+4)×(10+5)= (35+4)\times(10+5)=

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Step-by-step video solution

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00:00 Solve
00:03 Let's make sure to open parentheses properly
00:07 Each term in parentheses will multiply with each term in the second parentheses
00:27 Let's solve each multiplication and then sum
00:42 Let's solve one addition operation at a time
00:55 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

(35+4)×(10+5)= (35+4)\times(10+5)=

2

Step-by-step solution

We begin by opening the parentheses using the extended distributive property to create a long addition exercise:

We then multiply the first term of the left parenthesis by the first term of the right parenthesis.

We multiply the first term of the left parenthesis by the second term of the right parenthesis.

Now we multiply the second term of the left parenthesis by the first term of the left parenthesis.

Finally, we multiply the second term of the left parenthesis by the second term of the right parenthesis.

In the following way:

(35×10)+(35×5)+(4×10)+(4×5)= (35\times10)+(35\times5)+(4\times10)+(4\times5)=

We solve each of the exercises within parentheses:

350+175+40+20= 350+175+40+20=

We solve the exercise from left to right:

350+175=525 350+175=525

525+40=565 525+40=565

565+20=585 565+20=585

3

Final Answer

585

Practice Quiz

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\( 140-70= \)

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