Solve (35+4)×(10+5): Order of Operations Practice

Question

$(35+4)\times(10+5)=$

00:00 Solve

00:03 Let's make sure to open parentheses properly

00:07 Each term in parentheses will multiply with each term in the second parentheses

00:27 Let's solve each multiplication and then sum

00:42 Let's solve one addition operation at a time

00:55 And this is the solution to the question

We begin by opening the parentheses using the extended distributive property to create a long addition exercise:

We then multiply the first term of the left parenthesis by the first term of the right parenthesis.

We multiply the first term of the left parenthesis by the second term of the right parenthesis.

Now we multiply the second term of the left parenthesis by the first term of the left parenthesis.

Finally, we multiply the second term of the left parenthesis by the second term of the right parenthesis.

In the following way:

$(35\times10)+(35\times5)+(4\times10)+(4\times5)=$

We solve each of the exercises within parentheses:

$350+175+40+20=$

We solve the exercise from left to right:

$350+175=525$

$525+40=565$

$565+20=585$

585