Simplify the Expression: (a^20b/a^15b) × (a^3b/a^2b) Using Exponent Rules

Simplify the following problem:

a20ba15b×a3ba2b= \frac{a^{20b}}{a^{15b}}\times\frac{a^{3b}}{a^{2b}}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simplify the following problem
00:03 When dividing powers with equal bases
00:06 The power of the result equals the difference of exponents
00:11 We'll apply this formula to our exercise, and subtract the exponents
00:30 When multiplying powers with equal bases
00:35 The power of the result equals the sum of exponents
00:40 We'll apply this formula to our exercise, and add together the exponents
00:45 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Simplify the following problem:

a20ba15b×a3ba2b= \frac{a^{20b}}{a^{15b}}\times\frac{a^{3b}}{a^{2b}}=

2

Step-by-step solution

Let's start with multiplying the fractions, remembering that the multiplication of fractions is performed by multiplying the numerator by the numerator and the denominator by the denominator:

a20ba15ba3ba2b=a20ba3ba15ba2b \frac{a^{20b}}{a^{15b}}\cdot\frac{a^{3b}}{a^{2b}}=\frac{a^{20b}\cdot a^{3b}}{a^{15b}\cdot a^{2b}}

In both the numerator and denominator, multiplication occurs between terms with identical bases, thus we'll apply the power law for multiplying terms with identical bases:

cmcn=cm+n c^m\cdot c^n=c^{m+n}

We emphasize that this law can only be used when multiplication is performed between terms with identical bases.

From this point forward, we will no longer use the multiplication sign, instead we will place terms next to each other.
Let's return to the problem and apply the above power law separately to the fraction's numerator and denominator:

a20ba3ba15ba2b=a20b+3ba15b+2b=a23ba17b \frac{a^{20b}a^{3b}}{a^{15b}a^{2b}}=\frac{a^{20b+3b}}{a^{15b+2b}}=\frac{a^{23b}}{a^{17b}}

In the final step we calculated the sum of the exponents in the numerator and denominator.

Now we need to perform division between two terms with identical bases, thus we'll apply the power law for dividing terms with identical bases:

cmcn=cmn \frac{c^m}{c^n}=c^{m-n}

This law can only be used when division is performed between terms with identical bases.

Let's return to the problem and apply the above power law:

a23ba17b=a23b17b=a6b \frac{a^{23b}}{a^{17b}}=a^{23b-17b}=a^{6b}

In the final step we calculate the subtraction between the exponents.

This is the most simplified form of the expression:

Therefore, the correct answer is D.

3

Final Answer

a6b a^{6b}

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\( 112^0=\text{?} \)

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