3x⋅2x⋅32x= 3^x\cdot2^x\cdot3^{2x}= 3x⋅2x⋅32x=
In this case we have 2 different bases, so we will add what can be added, that is, the exponents of 3 3 3
3x⋅2x⋅32x=2x⋅33x 3^x\cdot2^x\cdot3^{2x}=2^x\cdot3^{3x} 3x⋅2x⋅32x=2x⋅33x
33x⋅2x 3^{3x}\cdot2^x 33x⋅2x