Insert the corresponding expression:
(2×87×19)2x+3y= \left(\frac{2\times8}{7\times19}\right)^{2x+3y}= (7×192×8)2x+3y=
22x+3y×82x+3y72x+3y×192x+3y \frac{2^{2x+3y}\times8^{2x+3y}}{7^{2x+3y}\times19^{2x+3y}} 72x+3y×192x+3y22x+3y×82x+3y