Insert the corresponding expression:
(3×74×8)b+1= \left(\frac{3\times7}{4\times8}\right)^{b+1}= (4×83×7)b+1=
3b+1×7b+14b+1×8b+1 \frac{3^{b+1}\times7^{b+1}}{4^{b+1}\times8^{b+1}} 4b+1×8b+13b+1×7b+1