Given the following trapezoid:
AAABBBCCCDDD57
Find the area of the trapezoid ABCD.
The area of the trapezoid will be:
S=(AB+DC)×h2 S=\frac{(AB+DC)\times h}{2} S=2(AB+DC)×h
We replace the known data in the formula:
(5+7)2×83= \frac{(5+7)}{2}\times\frac{8}{3}= 2(5+7)×38=
12×86= \frac{12\times8}{6}= 612×8=
966=16 \frac{96}{6}=16 696=16
16