Calculate 9 Times the Sum of 1/3 and 1/4

Solve the following expression:

$9(\frac{1}{3}+\frac{1}{4})=$

We'll use the distributive property and multiply 9 by each term in the parentheses:

$(9\times\frac{1}{3})+(9\times\frac{1}{4})=$

Let's solve the left parentheses. Remember that:

$9=\frac{9}{1}$

$\frac{9}{1}\times\frac{1}{3}=\frac{9\times1}{1\times3}=\frac{9}{3}$

Let's solve the right parentheses.

$\frac{9}{1}\times\frac{1}{4}=\frac{9\times1}{1\times4}=\frac{9}{4}$

Now we have the expression:

$\frac{9}{3}+\frac{9}{4}=$

Let's solve the left fraction:

$\frac{9}{3}=3$

For the right fraction, we'll separate the numerator into an addition problem:

$\frac{9}{4}=\frac{8+1}{4}$

We'll separate the fraction we got into an addition of fractions and get the expression:

$3+\frac{8}{4}+\frac{1}{4}=$

Let's solve the fraction:

$\frac{8}{4}=2$

And now we obtain:

$3+2+\frac{1}{4}=5\frac{1}{4}$