Calculate (2×7×5)³: Product of Numbers Raised to Third Power

Exponent Rules with Product Powers

(2×7×5)3= (2\times7\times5)^3=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:06 Let's simplify!
00:09 We'll use the formula for multiplying powers.
00:12 When you have a multiplication in parentheses raised to power N,
00:17 You raise each number inside separately to the power of N.
00:22 Now, let's apply this formula in our exercise!
00:26 And that's how we solve the question. Great job!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

(2×7×5)3= (2\times7\times5)^3=

2

Step-by-step solution

To solve the problem, we need to apply the power of a product exponent rule. This rule states that when you raise a product to a power, it's the same as raising each factor to that power. In mathematical terms, if you have (abc)n (abc)^n , it is equivalent to an×bn×cn a^n \times b^n \times c^n .

Let's apply this rule step by step:

Our original expression is: (2×7×5)3 (2 \times 7 \times 5)^3 .

We first identify the factors inside the parentheses as 2 2 , 7 7 , and 5 5 .

According to the Power of a Product rule, we can distribute the exponent3 3 to each factor:

First, raise 2 2 to the power of 3 3 to get 23 2^3 .

Then, raise 7 7 to the power of 3 3 to get 73 7^3 .

Finally, raise 5 5 to the power of 3 3 to get 53 5^3 .

Therefore, the expression (2×7×5)3 (2 \times 7 \times 5)^3 simplifies to 23×73×53 2^3 \times 7^3 \times 5^3 .

3

Final Answer

23×73×53 2^3\times7^3\times5^3

Key Points to Remember

Essential concepts to master this topic
  • Power of Product Rule: (abc)n=an×bn×cn (abc)^n = a^n \times b^n \times c^n
  • Technique: Distribute exponent 3 to each factor: 23×73×53 2^3 \times 7^3 \times 5^3
  • Check: Verify by calculating: 8×343×125=343,000 8 \times 343 \times 125 = 343,000

Common Mistakes

Avoid these frequent errors
  • Adding the exponent instead of distributing it
    Don't calculate 2×7×5+3=73 2 \times 7 \times 5 + 3 = 73 ! This treats the exponent like addition and ignores the power rule completely. Always distribute the exponent to each factor inside the parentheses using (abc)n=an×bn×cn (abc)^n = a^n \times b^n \times c^n .

Practice Quiz

Test your knowledge with interactive questions

\( 112^0=\text{?} \)

FAQ

Everything you need to know about this question

Why can't I just multiply 2×7×5 first and then cube it?

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You absolutely can do that! (2×7×5)3=(70)3=343,000 (2 \times 7 \times 5)^3 = (70)^3 = 343,000 . However, the question asks for the expanded form using the power of product rule: 23×73×53 2^3 \times 7^3 \times 5^3 .

How do I remember the power of product rule?

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Think of it like sharing! When you have (abc)3 (abc)^3 , the exponent 3 gets shared equally with each factor inside. So a gets cubed, b gets cubed, and c gets cubed.

What if there are more than 3 factors inside the parentheses?

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The rule works the same way no matter how many factors you have! For example: (abcd)2=a2×b2×c2×d2 (abcd)^2 = a^2 \times b^2 \times c^2 \times d^2 . Just distribute the exponent to every single factor.

Do I need to calculate the actual values of 2³, 7³, and 5³?

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Not unless the problem asks for it! The answer 23×73×53 2^3 \times 7^3 \times 5^3 is already in its correct expanded form. If you want the numerical answer: 8×343×125=343,000 8 \times 343 \times 125 = 343,000 .

What's the difference between (2×7×5)³ and 2×7×5³?

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Huge difference! In (2×7×5)3 (2 \times 7 \times 5)^3 , the parentheses mean everything gets cubed. In 2×7×53 2 \times 7 \times 5^3 , only the 5 gets cubed while 2 and 7 stay as they are.

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