Sarah receives a school assignment.
In the first hour, she does 82 of the work, while in the second hour she completes 41 of the work.
How much of the assignment does Sarah do in total?
To solve this problem, we will add the fractions of the work Sarah completed in the first and second hours:
- Step 1: Identify the fractions: Sarah completed 82 of the work in the first hour and 41 of the work in the second hour.
- Step 2: Convert the fractions to have the same denominator. The denominators are 8 and 4, respectively. The least common denominator (LCD) of 8 and 4 is 8.
- Step 3: Convert 41 to a fraction with a denominator of 8. Since 41=82, we convert it as follows:
41=4×21×2=82
- Step 4: Add the fractions with the common denominator:
82+82=82+2=84
- Step 5: Simplify the resulting fraction. Divide the numerator and the denominator by their greatest common divisor, which is 4:
84=8÷44÷4=21
Therefore, Sarah completed 21 of the assignment in total.