Parentheses in advanced Order of Operations: Using variables

We start by substituting the value of $X$

$(4+4)(3+4)$

First, we perform the calculation in parentheses

$(8)(7)$

After this, we solve the parentheses and can continue with the simple multiplication exercise.

$7\times 8=56$

We begin by solving the multiplication exercise:

$12\times(-5)=-60$

and subsequently the exercises within brackets:

$21-4=17$

We obtain the following:

$23-(-60)+y:7+17=107$

Keep in mind that a negative times a negative becomes a positive:

$23+60+y:7+17=107$

Next we simplify and add:

$23+60=83$

$83+17=100$

We obtain the following calculation:

$100+y:7=107$

We then rearrange the sections:

$y:7=107-100$

$\frac{y}{7}=7$

Lastly we multiply by 7:

$y=7\times7=49$