41a+31x+42a+81+83=?
\( \frac{1}{4}a+\frac{1}{3}x+\frac{2}{4}a+\frac{1}{8}+\frac{3}{8}=\text{?} \)
\( \frac{3}{4}+\frac{1}{8}m+\frac{2}{8}n+\frac{17}{8}m=\text{?} \)
\( \frac{x}{8}+\frac{31}{8}+\frac{x}{4}+\frac{1}{4}x+\frac{y}{8}=\text{?} \)
\( \frac{3}{8}a+\frac{14}{9}b+1\frac{1}{9}b+\frac{6}{8}a=\text{?} \)
\( \frac{1}{4a}+\frac{1}{2a}+\frac{x}{3}+\frac{4}{3}b+\frac{2}{3}x=\text{?} \)
\( \frac{2}{3}a+\frac{1}{4}b+\frac{1}{8}c+\frac{1}{4}a=\text{?} \)
\( \frac{2}{5}x+\frac{4}{3}y+\frac{7}{9}x+\frac{3}{4}y=\text{?} \)
\( 6\frac{4}{5}x+7\frac{1}{2}x+4\frac{1}{3}x\cdot7.3x=\text{?} \)
\( \frac{4}{7}x+\frac{5}{7}y+\frac{3}{4}x+\frac{8}{9}y=\text{?} \)
\( 3\frac{b}{a}\cdot1\frac{3}{8}a+\frac{5}{8}b+\frac{4}{18}m+\frac{9}{10}a+\frac{2}{3}m=\text{?} \)
\( \frac{3z}{4}+\frac{1}{4}m+\frac{12}{13}z\cdot\frac{4}{5}m+\frac{1}{7}z=\text{?} \)
\( (\frac{3}{4}+2a)(8a+9ba)-(5+a)(\frac{3}{2}a+b)=\text{?} \)