18x−7+4x−9−8x=?
\( 18x-7+4x-9-8x=\text{?} \)
\( 7.3\cdot4a+2.3+8a=\text{?} \)
\( 3x+4x+7+2=\text{?} \)
\( 3z+19z-4z=\text{?} \)
\( 7a+8b+4a+9b=\text{?} \)
To solve the exercise, we will reorder the numbers using the substitution property.
To continue, let's remember an important rule:
1. It is impossible to add or subtract numbers with variables.
That is, we cannot subtract 7 from 8X, for example...
We solve according to the order of arithmetic operations, from left to right:
Remember, these two numbers cannot be added or subtracted, so the result is:
It is important to remember that when we have numbers and variables, it is impossible to add or subtract them from each other.
We group the elements:
29.2a + 2.3 + 8a =
And in this exercise, this is the solution!
You can continue looking for the value of a.
But in this case, there is no need.
\( 13a+14b+17c-4a-2b-4b=\text{?} \)
\( a+b+bc+9a+10b+3c=\text{?} \)
\( 35m+9n-48m+52n=? \)
\( 8y+45-34y-45z=\text{?} \)
\( 5a+3a+8b+10b=\text{?} \)
\( 3.4-3.4a+2.6b-7.5a=\text{?} \)
\( 7.8+3.5a-80b-7.8b+3.9a=\text{?} \)
\( 39.3:4a+5a+8.2+13z=\text{?} \)
\( 5.6x+7.9y+53xy+12.1x=\text{?} \)
\( \frac{1}{4}a+\frac{1}{3}x+\frac{2}{4}a+\frac{1}{8}+\frac{3}{8}=\text{?} \)
\( \frac{3}{8}a+\frac{14}{9}b+1\frac{1}{9}b+\frac{6}{8}a=\text{?} \)