Verify the Equation: Is (8+3×4)/(6×2+8) = 1?

Let's examine the given problem:

$\frac{8+3\cdot4}{6\cdot2+8}\stackrel{?}{= }1$Note that in the numerator there is a product between the number 8 and the number$3\cdot4$and in the denominator there is a product between the number 8 and the number $6\cdot2$, since these two multiplications give the same result:

$3\cdot4=6\cdot2=12$Both in the numerator and denominator it's the same number:

$8+3\cdot4=6\cdot2+8$ Now we'll remember that dividing a number by itself always yields 1, therefore indeed:

$\frac{8+3\cdot4}{6\cdot2+8}= \frac{8+12}{12+8}\stackrel{!}{= }1$ and thus answer A is the correct answer