Triangle Similarity Theorem: Finding the Ratio between ABC and DEF

Question

According to which theorem are the triangles similar?

What is their ratio of similarity?

2x2x2x4z4z4zyyy2z2z2zxxxAAABBBCCCDDDEEEFFF

Video Solution

Solution Steps

00:00 According to which theorem are the triangles similar? And what is the similarity ratio?
00:03 Let's find the similarity ratio between the sides
00:09 Let's substitute appropriate values according to the given data and find the ratio
00:12 This is the ratio, if it's equal for all sides then the triangles are similar
00:16 Let's check another pair of sides
00:25 The ratio matches
00:30 And let's check the last pair of sides
00:38 Here too the ratio matches
00:45 The triangles are similar according to SSS
00:49 And this is the solution to the question

Step-by-Step Solution

Using the given data, the side ratios can be written as follows:

FDAB=X2X=12 \frac{FD}{AB}=\frac{X}{2X}=\frac{1}{2}

FEAC=y2y=y2y=12 \frac{FE}{AC}=\frac{\frac{y}{2}}{y}=\frac{y}{2y}=\frac{1}{2}

DEBC=2Z4Z=24=12 \frac{DE}{BC}=\frac{2Z}{4Z}=\frac{2}{4}=\frac{1}{2}

We can therefore deduce that the ratio is compatible with the S.S.S theorem (Side-Side-Side):

FDAB=FEAC=DEBC=12 \frac{FD}{AB}=\frac{FE}{AC}=\frac{DE}{BC}=\frac{1}{2}

Answer

S.S.S., 12 \frac{1}{2}