Solve the Quartic Equation: x^4/16 = 1

Quartic Equations with Fourth Root Solutions

Solve the following problem:

x416=1 \frac{x^4}{16}=1

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find X
00:03 Isolate X
00:17 Extract root
00:24 When extracting a root there are always 2 solutions (positive, negative)
00:28 Any number squared is always greater than 0 (non-negative)
00:31 Extract root
00:34 When extracting a root there are always 2 solutions (positive, negative)
00:37 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following problem:

x416=1 \frac{x^4}{16}=1

2

Step-by-step solution

Let's solve the given equation:

x416=1 \frac{x^4}{16}=1

Perform the inverse operation of the fourth power (that applies to the unknown) on both sides of the equation. This is the fourth root operation. We will need to apply several laws of exponents:

a. Definition of root as a power:

an=a1n \sqrt[n]{a}=a^{\frac{1}{n}} and two laws of exponents:

b. Law of exponents for power of a power:

(am)n=amn (a^m)^n=a^{m\cdot n}

c. Law of exponents for power applied to a product in parentheses:

(ab)n=anbn \big(\frac{a}{b}\big)^n=\frac{a^n}{b^n}

Proceed to solve the equation:


x416=1/4x44164=±14(x4)142=±1x4142=±1x2=±1/2x=2,2 \frac{x^4}{16}=1 \hspace{8pt}\text{/}\sqrt[4]{\hspace{6pt}}\\ \frac{\sqrt[4]{x^4}}{\sqrt[4]{16}}=\pm\sqrt[4]{ 1}\\ \frac{(x^4)^{\frac{1}{4}}}{2}=\pm1\\ \frac{x^{4\cdot\frac{1}{4}}}{2}=\pm1\\ \frac{x}{2}=\pm1\hspace{8pt}\text{/}\cdot 2\\ \boxed{x=2,-2}

In the first stage, we applied the fourth root to both sides of the equation. We then applied the definition of root as a power (a.) on the left side and the law of exponents for power applied to a product in parentheses (c.). Raising 1 to any power always yields 1. In the next stage, we applied the law of exponents for power of a power (b.) to the fraction's numerator on the left side, and remembered that raising a number to the power of 1 doesn't change the number. Finally, we eliminated the fraction on the left side by multiplying both sides of the equation by the common denominator - which is the number 2.

Furthermore, due to the fact that an even power doesn't maintain the sign of the number it's applied to (it will always give a positive result), taking an even root of both sides of the equation requires considering two possible cases - positive and negative (this is unlike taking a root of an odd order, which requires considering only one case that matches the sign of the number the root is applied to),

Therefore, the correct answer is answer c.

3

Final Answer

x=±2 x=\pm2

Key Points to Remember

Essential concepts to master this topic
  • Rule: Apply the fourth root to both sides to solve x4=16 x^4 = 16
  • Technique: Use 164=2 \sqrt[4]{16} = 2 and remember even roots give ±
  • Check: Verify both solutions: (2)4/16=16/16=1 (2)^4/16 = 16/16 = 1 and (2)4/16=16/16=1 (-2)^4/16 = 16/16 = 1

Common Mistakes

Avoid these frequent errors
  • Forgetting the negative solution when taking even roots
    Don't write just x = 2 = wrong! Even powers eliminate signs, so (-2)^4 = 16 just like (2)^4 = 16. Always include both positive and negative solutions when taking even roots.

Practice Quiz

Test your knowledge with interactive questions

Determine if the simplification shown below is correct:

\( \frac{7}{7\cdot8}=8 \)

FAQ

Everything you need to know about this question

Why do I get two answers instead of one?

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Because even powers like x^4 always give positive results! Both 2^4 = 16 and (-2)^4 = 16, so both values satisfy the original equation.

How do I know when to use ± in my answer?

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Use ± when taking even roots (square root, fourth root, sixth root, etc.). Odd roots like cube roots only give one answer that matches the original sign.

What if I multiply both sides by 16 instead?

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That works too! You get x4=16 x^4 = 16 , then take the fourth root of both sides. Either method gives the same answer: x=±2 x = ±2 .

Is x = 16 ever correct for this type of problem?

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No! Check it: 164/16=65536/16=40961 16^4/16 = 65536/16 = 4096 ≠ 1 . Always substitute your answer back to verify it works!

Why can't x = 0 be a solution?

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Substitute and see: 04/16=0/16=01 0^4/16 = 0/16 = 0 ≠ 1 . Zero raised to any positive power is still zero, not 1.

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