Solve the Integer Equation: -30-(-2)+(-8)+5

Question

Solve the following equation:

$-30-(-2)+(-8)+5=$

00:00 Solve

00:03 Negative times negative always equals positive

00:07 Open parentheses

00:13 Take 2 jumps right (to the positive side) on the axis

00:22 This is the solution to the operation

00:33 Take 8 jumps left (to the negative side) on the axis

00:46 This is the solution to the operation

01:00 Take 5 jumps right (to the positive side) on the axis

01:20 And this is the solution to the question

Let's begin by applying the following rule in order to rewrite the equation:

$-(-x)=+$

$-30+2+(-8)+5=$

$-28+(-8)+5=$

Next we will locate negative 28 on the number line and proceed 8 steps to the left (since negative 8 is less than zero):

We reach negative 36.

Resulting in the following exercise:

$-36+5=$

Next we locate negative 36 on the number line and proceed 5 steps to the right (since 5 is greater than zero):

We reach negative 31

$-31$