Solve Linear Equation: Finding Y in 2y-5y+12+30=0

Question

2y+125y+30=0 2y+12-5y+30=0

y=? y=\text{?}

Video Solution

Solution Steps

00:00 Solve
00:03 We want to isolate the unknown Y
00:07 Let's group terms
00:14 Let's arrange the equation so that one side has only the unknown Y
00:23 Let's isolate the unknown Y
00:34 And this is the solution to the question

Step-by-Step Solution

To solve the equation 2y+125y+30=0 2y + 12 - 5y + 30 = 0 , follow these steps:

  • Step 1: Simplify the equation by combining like terms.
    Combine the y y terms and the constant terms:
    2y5y+12+30=0 2y - 5y + 12 + 30 = 0
  • Step 2: Calculate the combined terms.
    2y5y=3y 2y - 5y = -3y
    12+30=42 12 + 30 = 42
    Thus, the equation becomes:
    3y+42=0 -3y + 42 = 0
  • Step 3: Isolate the variable y y .
    Subtract 42 from both sides to get:
    3y=42 -3y = -42
  • Step 4: Solve for y y by dividing both sides by 3-3:
    y=423 y = \frac{-42}{-3}
  • Step 5: Simplify the fraction:
    y=14 y = 14

Therefore, the solution to the equation is y=14 y = 14 .

Answer

14 14