Solve for Missing Numerator in (?)/(39x³-13x²) = 7/(13x²)

Question

Complete the corresponding expression in the numerator

?39x313x2=713x2 \frac{?}{39x^3-13x^2}=\frac{7}{13x^2}

Video Solution

Step-by-Step Solution

Let's examine the problem:

?39x313x2=713x2 \frac{?}{39x^3-13x^2}=\frac{7}{13x^2} First let's check that in the fraction's numerator on the left side there is an expression that can be factored using factoring out a common factor, we will therefore factor out the largest possible common factor (meaning that the expression remaining in parentheses cannot be further factored by taking out a common factor):

?39x313x2=713x2?13x2(3x1)=713x2 \frac{?}{39x^3-13x^2}=\frac{7}{13x^2} \\ \downarrow\\ \frac{?}{13x^2(3x-1)}=\frac{7}{13x^2} \\ In factoring, we used of course the law of exponents:

am+n=aman \bm{a^{m+n}=a^m\cdot a^n}

Let's continue solving the problem, think logically, and remember the fraction reduction operation, note that in the fraction's numerator both on the right side and on the left side there is the expression:13x2 13x^2 ,
therefore we don't want it to be reduced from the fraction's numerator on the left side, however, the expression:3x1 3x-1 , is not found in the fraction's numerator on the right side (which is the fraction after reduction) therefore we can conclude that this expression needs to be reduced from the fraction's numerator on the left side,

Additionally, let's consider the number 7 which appears in the fraction's numerator on the right side (which is the fraction after reduction) but is not found in the fraction's numerator on the left side, meaning - we want it to be included in choosing the missing expression (which is the product of the desired expressions - in order to get the fraction on the right side after reduction)

Therefore the missing expression must be none other than:

7(3x1) 7(3x-1)

Let's verify that from this choice we indeed get the expression on the right side: (reduction sign)

?13x2(3x1)=713x27(3x1)13x2(3x1)=?713x2713x2=!713x2 \frac{?}{13x^2(3x-1)}=\frac{7}{13x^2} \\ \downarrow\\ \frac{\textcolor{red}{7(3x-1)}}{13x^2(3x-1)}\stackrel{?}{= }\frac{7}{13x^2} \\ \downarrow\\ \boxed{\frac{7}{13x^2} \stackrel{!}{= }\frac{7}{13x^2} }

and therefore choosing the expression:

7(3x1) 7(3x-1)

is indeed correct.

From opening the parentheses (using the distributive law) we can identify that the correct answer is answer D.

Answer

21x7 21x-7